Math help!! word problems!?

Question

A bus traveling 40 mph and a car traveling 50 mph cover the same distance. the bus travels 1 hour more then the car. how many hours did the car travel?

Answer 1

40(t +1) = 50 t

40t + 40 = 50 t

40 = 10t

40/10 = t

4 = t

Answer 2

Rate X Time = Distance
T= time in hours the car traveled, therefore:
40 mi/ hr X (T+1) = D, and 50 mi/ hr X T= D, which means that
40T + 40 = 50T since both vehcles travel the same distance.
Subtracting 40T from both sides gives us 40= 10T meaning
that T= 4 hours. Both vehicles travel 200 miles.

Answer 3

t : the time the car travel
the distance the bus travel :
40*(t + 1)
the distance the car travel :
50*t
because they travel the same distance =>
40*(t + 1) = 50*t =>
40t + 40 = 50t =>
40 = 50t - 40t =>
t = 4

Answer 4

Sorry not going to answer a home work question. Will help you figure out how to answer. Draw a picture. My favorite math prof. taught me to do it. Literally draw a picture - make it a stick figure of a car, a bus, show the speed and the question (what is T where T = time).

Answer 5

If some thing is 40% smaller, you in reality subtract 40%. So 40% of 40 energy is 16: you're trying this by ability of multiplying 40 by ability of 0.4. the reply will be 40 - 16 = 24 A shorter way would merely be to multiply by ability of 40 by ability of 0.6, because that it really is a million-0.4.

Answer 6

4 hours

Answer 7

so let x= hour
distance =rate times hour
so
the distance of bus is = to the distance of car
therefore
40(x+1)=50x
40x+40=50x
10x=40hours
x=4hours

Answer 8

200

Answer 9

Guess and check

The car went 200 miles in 4 hours

Answer 10

200 miles or 4 hours