what is the square root of (-5 +12i)
I put this question up in a pub, offering a free pint to the one who answered first correctly, noone won the pint, and I eventualy had to reviel the answer myself. But I think there isn`t many smart people in my local.
By the way there are two answers and the person who gives both answers first will win the points, I would give you a pint, but pints can`t be sent by e-mail sorry.
2006-06-15 13:30:18 · 14 answers · asked by MARTIN B 4 in Science & Mathematics ➔ Mathematics
by the way the question spoken is what is the square root of minus five plus twelve eye. Noone has given the right answers yet.
2006-06-15 13:37:33 · update #1
Captain char you are wrong because 2-3i squared = -5 -12i
2006-06-15 13:56:52 · update #2
I think Scott R is going to get the points , but I cant give them to you until 24 hours have passed, be patient.
2006-06-15 15:19:44 · update #3
2 + 3i
-2 - 3i
NO FAIR YOU PEOPLE WHO ARE EDITING YOUR ANSWERS WITH THE CORRECT ONE
I WAS FIRST, THANK YOU (MIKESGLOBAL & dhaval70
YOU CHEAT)
Thank you for being honest dhaval70.
boy i could go for a pint right now....
2006-06-15 13:40:36 · answer #1 · answered by Scott R 6 · 9⤊ 0⤋
2+3i
2006-06-15 13:44:25 · answer #2 · answered by fawkesopel 1 · 0⤊ 0⤋
The answers are:
2 + 3i, and
-2 - 3i
2006-06-15 13:47:37 · answer #3 · answered by AO 1 · 0⤊ 0⤋
Probably the most straight forward way is
(a + ib)^2 = a^2 - b^2 + 2iab = -5 +12i
a^2 - b^ 2 = -5 , ab =6
solving for a, a =2, and b = 3 and a = -2. and b =-3
so 2 + 3i and -2 - 3i are the roots
2006-06-15 14:05:54 · answer #4 · answered by Jeffrey D 2 · 0⤊ 0⤋
First of all, you have used the phrase "what is the square root of (-5 +12i)," this implies singularity. If you want to know what the square ROOTS of -5+12i ARE, then they are ±(2+3i).
2006-06-15 13:41:29 · answer #5 · answered by Eulercrosser 4 · 0⤊ 0⤋
2+3i
cause (2 + 3i) x (2 + 3i) = 4 + 6i + 6i + 9i^2 = 4 + 6i + 6i - 9 = -5 + 12i
alright Scott R you were first, it's just stupid of me to forget that one.
2006-06-15 13:39:41 · answer #6 · answered by dhaval70 2 · 0⤊ 0⤋
let me see if I can answer this...
The first root of (-5 + 12i) is (2 + 3i)
The second is...well, duh...(-2 - 3i). Right???
Am I right??
2006-06-15 13:34:27 · answer #7 · answered by mikesglobal 3 · 0⤊ 0⤋
If i is the square root of negative 1 which is an imaginary number, it could be almost anything I imagine.
I'm imagining 10 points
2006-06-15 13:40:54 · answer #8 · answered by texasben 2 · 0⤊ 0⤋
let x = 10's digit let y = gadgets digit 4x + y = 18 y = 18 - 4x 10y + x = 2(10x + y) - 9 10y + x = 20x + 2y - 9 8y - 19x = -9 8(18 - 4x) - 19x = -9 one hundred 44 - 32x - 19x = -9 -51x = -153 x = 3 y = 6 unique huge type is 36
2016-10-14 05:05:44 · answer #9 · answered by Anonymous · 0⤊ 0⤋
+/-(2+3i)
2006-06-15 13:53:56 · answer #10 · answered by neetu s 1 · 0⤊ 0⤋