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How Hyper Are YOU? Why are you hyper? and why are you the most hyper?

2006-06-15 12:51:45 · 4 answers · asked by Anonymous in Society & Culture Other - Society & Culture

4 answers

I'M HYPERRRR! I'M HYPERRRR I'M HYPERRRR! I'M HYPERRRR! I'M HYPERRRR I'M HYPERRRR!I'M HYPERRRR! I'M HYPERRRR I'M HYPERRRR! I'M HYPERRRR! I'M HYPERRRR I'M HYPERRRR!I'M HYPERRRR! I'M HYPERRRR I'M HYPERRRR! I'M HYPERRRR! I'M HYPERRRR I'M HYPERRRR!I'M HYPERRRR! I'M HYPERRRR I'M HYPERRRR! I'M HYPERRRR! I'M HYPERRRR I'M HYPERRRR!I'M HYPERRRR! I'M HYPERRRR I'M HYPERRRR! I'M HYPERRRR! I'M HYPERRRR I'M HYPERRRR!I'M HYPERRRR! I'M HYPERRRR I'M HYPERRRR! I'M HYPERRRR! I'M HYPERRRR I'M HYPERRRR! COFFIE!! COFFFIE COFFIE COFFIE COFFIE!!!!!! COFFIE!! COFFFIE COFFIE COFFIE COFFIE!!!!!! COFFIE!! COFFFIE COFFIE COFFIE COFFIE!!!!!! COFFIE!! COFFFIE COFFIE COFFIE COFFIE!!!!!! YEEEEAHHHHHH!!!!!

2006-06-15 12:55:44 · answer #1 · answered by Rachel :) 3 · 1 1

I have figured this out mathmatically:

x^2 – 4x – 5
5 - 1 = -4, -1 (5) = -5
(x+5),(x-1)
x = -5
x = 1

x^2+4x-5=0
x^2+4x=5
4/2 = (2)^2 = 4
x^2+4x+4=5+4
x^2+4x=9
(x+2)^2= 9
sqrt (x+2)^2 = sqrt 9
x+2= 3
x= -2 +/-3
x=1, x=-5

x= -4+/- sqrt 4^2-4(1)(-5)/2
x= -4+/- sqrt 16+20/2
x= -4+/- sqrt 36/2
x= -4+/- 6/2
x= -2+/- 6 = 1 or -5

For the function y = x2 - 4x - 5, y=(x – 2)^2 + 9

y+5=x^2-4
y+5+4=x^2-4x+4
y+9=(x-2)^2
y=(x – 2)^2 + 9
f(2) = 2^2 -4(2) – 5 = 4 – 8 – 5 = 9 the vertex is (2,9) or f(x) = (x -2)^2 + 9

Explanation of graphing. It is pretty? Or, Since a > 0 we know that it points upwards and if we know that the vertex is (2,9) we are good to go because we know that the lowest point of the parabola is (h,k) or (2,9). Also if we fold f along the axis of symmetry which is x = a, then f(a+k) = f(a-k) for every value of k. I like that it is pretty better, but I don’t make the rules (thank heavens).

It sorta kinda looks like the same thing as y = a (x – h)2 + k. Only the vertex is different where it does touch the x axis; however it still fails to cross the x axis.

S(t) = -16t^2 + 64t

S(t) = 48
= -16(1)^2 + 64(1)
= -16+64
= 48

S = 64
0 = -16(t)^2 + 64(t)/2(-16)
0 = -64 +/- sqrt 64-4(16)/32
0 = - 64 +/- 64/32
0 = 128/32 = 4
0 = 0/32 = 0
64 feet, 2 sec

T = - 64/2(-16) = -64/-32 = 2

s(2) = -16(2)^2 + 64(2)
s(2) = -64 + 128
s(2) = 64

75 feet by 75 feet
W + L + W = 300 or L = 300 – 2W/2
A = LW
A = (300 – 2W) W
A = 300W – 2W^2
W = - 300/2(-2) = 75
L = 300 – 2W/2
L = 300 – 2(75)/2
L = 150/2
L = 75

So as you can see (even tho I couldn't put the graphs in here) the answer to how hyper I am is 75.

2006-06-16 18:27:14 · answer #2 · answered by Airplanegirl 6 · 0 0

With one spoonful of suger I can run a mile marathon and talk on a cell phone.

2006-06-15 19:55:07 · answer #3 · answered by Anonymous · 0 0

NEXT QUESTION

2006-06-15 20:08:32 · answer #4 · answered by Anonymous · 0 0

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