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Lets assume I am throwing in a dome (no wind), and it is at Sea Level, Barometric Pressure is 760 and the humidity is 0%. A baseball is a sphere, 5 ounces, 9 inches in circumference (for calculating air resistance), and the ball has backspin on it upon release from my hand. Please don't say 428 feet either, that's not correct, although some others have said so (think they forgot to calculate air resistance). Good Luck. ( I REALLY WANT TO KNOW THIS, ANY HELP IS APPRECIATED, ESPECIALLY FROM MATH WIZZES!)

2006-06-15 11:04:50 · 7 answers · asked by sretih 1 in Sports Baseball

7 answers

80 mph, 25 rev/sec (backspin), released 6.5 feet above the ground, two seam orientation - distance = 282.5 feet.

80 mph, 25 rev/sec (backspin), released 6.5 feet above the ground, four seam orientation - distance = 281.9 feet.

80 mph, 10 rev/sec (backspin), released 6.5 feet above the ground, two seam orientation - distance = 277.6 feet.

80 mph, 50 rev/sec (backspin), released 6.5 feet above the ground, two seam orientation - distance = 317.5 feet.

2006-06-16 11:21:46 · answer #1 · answered by ic3d2 4 · 3 0

OK genius, ask a math person, this is for sports fans not necessarily the smartest people in math. if you ask a stat or something I'd be able to tell ya

2006-06-24 04:28:49 · answer #2 · answered by Southie9 5 · 0 0

This is a physics question. Go find a basic physics book and plug the formula!

2006-06-26 07:58:43 · answer #3 · answered by S. Leroy 3 · 0 0

93 million miles.

2006-06-15 12:02:54 · answer #4 · answered by Dusty 7 · 0 0

screw math and throw the freakin' ball

2006-06-27 07:09:30 · answer #5 · answered by Mike S 2 · 0 0

i'm sorry i've lost the point

2006-06-26 00:21:14 · answer #6 · answered by V_for_VENDETTA 3 · 0 0

measure it when you actually do it

2006-06-15 12:17:39 · answer #7 · answered by a79518 2 · 0 0

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