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2006-06-15 09:42:29 · 4 answers · asked by jb62877 1 in Science & Mathematics Chemistry

4 answers

methalated - no such thing ... methylated - yes this is so ...

to methylate: R-H + MeH ... -> R-Me typically requires a good leaving group
to form the C-C bond.

For instance ... R-OH + ButylLi -> R-Li + MeI -> R-Me + LiI ...
in this most general case methyl iodide displaces a Lithiated intermediate,
which then is C-C formed via halogenated methyl reagent.

This is classic synthetic organic chem - and if this question is related to illicit drug synthesis, then I think you are asking in the wrong forum (i.e. psuedo ephedrine ... etc) .

cheers,
chem e

2006-06-15 10:48:07 · answer #1 · answered by chemical_engr 2 · 0 0

I presume you mean a "methylated" alkaloid.

You could use any of a number of known synthetic methods to add a methyl group. It depends on what functional groups you have to work with. You could do it with enolates, Grignard reagents, Gilman Reagents, etc.

ChemE:

If you use butyl lithium on R-OH, you'd expect the alcohol to be deprotonated. Reacting it with MeI would be an SN2-type Williamson ether synthesis. Atleast that's what it looks like from here.

2006-06-15 17:21:29 · answer #2 · answered by niuchemist 6 · 0 0

using synthetics, obviously.
i would probably use a positively charged ion or a magnet.

2006-06-15 16:46:10 · answer #3 · answered by dacrunklobsta 2 · 0 0

with iron

2006-06-15 17:25:55 · answer #4 · answered by ashish v 2 · 0 0

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