need to know how to solve
2006-06-15 07:29:06 · 15 answers · asked by gsusio 1 in Science & Mathematics ➔ Mathematics
3/x + 1 the way you put it..
2006-06-15 11:28:19 · answer #1 · answered by Vivek 4 · 0⤊ 1⤋
3/x +1
2006-06-15 15:20:05 · answer #2 · answered by Anil 1 · 0⤊ 0⤋
Assuming that the equation is:
1/x + 2/(x+1) =?
and NOT 1/x + (2/x) + 1.
what is 1/x + 2/(x+1) =?
Get Common Denominators:
Common Denominator is x(x+1)
=>
{(x+1)+2*x}/{x(x+1)}=
{3*x+1}/{x(x+1)}
This simplifies the equation but as others mentioned, did you mean the following?
1/x + 2/(x+1) =0
or
1/x + 2/x + 1 = 0
or what?
Your eq is lacking something if you are trying to solve for x given the function f(x)=y, where your function seems to be
f(x)=1/x + 2/x+1 = y. The way you wrote the function was not complete. Plus the way you wrote it without paranthesis implies theis function where it is the following:
1/x + 2/x +1 =y. This is because in Math, you mult & division are done before addition & subtraction going from left to right, except if you use paranthesis. Supposing you meant y to be 0 and the function to be 1/x +2/(1+x) then to solve for x countinuing from above=>
1/x +2/(1+x)=
{(x+1)+2*x}/{x(x+1)}=
{3*x+1}/{x(x+1)}=0
=>
3x=-1
x= -1/3
Yet, maybe I am misinterpretting your equation. I can help you if you supply the correct equations. As others have indicated, something is missing from your equation. Given the correct equation, we can help you solve the function for x.
2006-06-15 14:44:55 · answer #3 · answered by JosyMaude 3 · 0⤊ 0⤋
3/x+1=
3/x=-1
2006-06-15 14:34:25 · answer #4 · answered by charles f 1 · 0⤊ 0⤋
It's called a hyperbola. To graph it, put in random numbers for x and solve, like 1, 2, -1, -2, 1/2, 1/4, -1/2, etc. The function is undefined at x=0. The graph in the Quadrant 1 will be a U-shaped line that approaches that x-axis and the y-axis, but never touches it. You'll see the same thing in Quadrant 3 for negative values. The graph will never enter Quadrant 2 or 4.
2006-06-15 14:39:44 · answer #5 · answered by Stephen I 1 · 0⤊ 0⤋
(1/x) + (2/x) + 1 = 0
((1+2)/x) +1 = 0 Both 1/x and 2/x has the same denominator so we can add both.
((1+2)/x) = -1 Next, we put +1 to the other side of the equation and becomes -1.
(3/x) = -1 Next, we add 1+2 = 3.
x(3/x) = (-1)x After that, multiply both sides by x (we multiply the equation by x so that it will become a numerator).
3 = -x
x = -3 This is the final answer.
I hope that you got it.
2006-06-15 14:52:07 · answer #6 · answered by marbieisback 2 · 0⤊ 0⤋
x = -3
1/-3 + 2/-3 + 1 = 0
2006-06-15 14:42:01 · answer #7 · answered by flymarissa 1 · 0⤊ 0⤋
3+x/x
2006-06-15 15:26:40 · answer #8 · answered by ski racer 2 · 0⤊ 0⤋
x = -3
2006-06-15 15:11:25 · answer #9 · answered by sikandar 2 · 0⤊ 0⤋
looks like 3/x + 1. Without the right hand side of the equation, it's hard to solve.
2006-06-15 14:34:51 · answer #10 · answered by bequalming 5 · 0⤊ 0⤋
=3/x +1 or
I will play along
did you mean 1/x + 2/x+1 =0?
then X= -3
2006-06-15 14:33:28 · answer #11 · answered by Edward 7 · 0⤊ 0⤋