how can i check the leght of an in in c, not c++ Suppose i have an id number 03203, how to get value 5?

Answer 1

#include
#include

int main()
{
char *c;
sprintf(c, "03203");
return strlen(c);
}

Answer 2

Well, an integer can't have a leading 0, so your number is 3203, and it's "length" is 4, not 5. If you have a leading 0, then it is stored in a character array, and you can simply use strlen() to get the length of the string. The fact that it is an "id number", and consists of all digits, doesn't matter. It's how it is stored that makes the difference.

To get the number of digits in an integer, simply use the log10() function.

int x = 4321;
int b = (int) log10((double) x);

b should be 4.

Answer 3

You may need to convert it to a string for this to work...

int count = 0;
int i;

for (i = 0; your_id_number[i] != '\0'; i++)
{
count++;
}

count will return the length of your_id_number.