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What happens when water at a temperature of about 8 degree C dips to 3 degree C?

2006-06-15 06:31:07 · 4 answers · asked by balakrishnan c 1 in Science & Mathematics Physics

4 answers

Water has a density maxima at 4C

2006-06-15 06:35:41 · answer #1 · answered by scott_d_webb 3 · 0 0

Not quite sure where you're going with this but several things that certainly will happen are:

The water will get more dense (water is densest at 4 degrees C).

The cooling water will give off 5 calories of heat per gram (or, if you prefer, 9 BTUs per pound) over that temperature range.

It will be more viscous (ever so slightly more like syrup, pouring more slowly and being harder to pump).

Its refractive index (an optical property) will increase a bit with its increased density.

Hope that helps,
David
Kenai, Alaska

2006-06-15 06:42:41 · answer #2 · answered by David in Kenai 6 · 0 0

For water to exist as a liquid at 8 deg C, it would have to be under a vacuum. The pressure at this temperature would be approximately 1.072 kPa. Keep in mind, atmospheric pressure is about 101.3 kPa. For water to exist as a liquid at 3 deg C, the pressure would have to be 0.757 kPa. So the difference in pressure between 8 deg C and 3 deg C is .315 kPa.

Another thing that happens to water when the temperature drops from 8 deg C to 3 deg C is the internal energy (U) drops from 33.6 kJ/kg to 12.6 kJ/kg respectively.

2006-06-15 07:17:56 · answer #3 · answered by djsaultnutz 1 · 0 0

The water trends to increase the temperature according to the total amount of water dipped.
if the amounts are the same, the Temp will be about 5.5 celsius.

The more water you dipped, the more temperature you will get. The limit is 8 c.

Temperature equilibria, my friend.

2006-06-15 06:41:10 · answer #4 · answered by e647553us 1 · 0 0

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