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I just can't seem to get this one. The first one to get it gets the best answer.

2006-06-15 04:17:43 · 11 answers · asked by Anonymous in Science & Mathematics Mathematics

All of the answers below seem to give me the right answer for the first equation but not the right answer for the second one. I keep getting -10 for the answer to the second equation, although it is 7.

2006-06-15 04:37:13 · update #1

NOTE: THE ANSWER MUST HOLD TRUE FOR BOTH EQUATIONS, NOT JUST THE FIRST ONE.

2006-06-15 04:39:12 · update #2

11 answers

Given 3x - 2y = 5, if you follow the suggestion in the first answer and multiply it by 2 you get

6x - 4y = 10

and if you add this and the second equation you get

0x + 0y = 17 or 0 = 17, indicating that there is no solution to this simultaneous pair. Why, you might ask - if you solve each equation for y you get

y = 3x/2 - 5/2 and
y = 6x/4 + 7/4

The coefficient of x in the second equation reduces to 3/2, so these equations have the same slope and are therefore parallel.

2006-06-15 04:47:29 · answer #1 · answered by Anonymous · 3 2

you have to add it like this:
3x-2y=5
-6x+4y=7
multiply the first equation by 2 it will be
6x-4y=10
-6x+4y=7 then when you add it will be 17, there is no answer for x nor y but the answer for both equations is 17

2006-06-15 09:09:57 · answer #2 · answered by fabrice2k5 3 · 0 0

the first element you may observe is that the left aspect of both equations are similar. in case you multiply the right left aspect by ability of (-2), then you absolutely get: -6x+4y, it really is the left aspect of the bottom equation. although, 5*(-2) = -10, no longer 7! This tells you that the gadget has no authentic answer.

2016-10-14 04:42:35 · answer #3 · answered by ? 4 · 0 0

3x - 2y = 5
-6x + 4y = 7

3x - 2y = 5
-2y = -3x + 5
y = (3/2)x - (5/2)

-6x + 4y = 7
4y = 6x + 7
y = (3/2)x + (7/4)

as you can see, the 2 problems have the same slope, but different y-intercepts, which would make them parallel, so there are no solutions

ANS : No Solutions

2006-06-15 05:40:30 · answer #4 · answered by Sherman81 6 · 0 0

I think this equation has no solution. Do it by the graphic method to check it.

( 3x-2y=5) 2
-6x+4y=7
----------
6x - 4y = 10
-6x +4y = 7
---------------
= 17

Maybe its one of those "parallel" equations with no answer.

[EDIT]
I just checked the answer with other method... this system has no answer.

3x-2y=5
-6x+4y=7

x=(5+2y)/3 You replace this in the second equation.
(-6(5+2y)/3) + 4y = 7
-10 -4y + 4y = 7
-10 = 7

So it means no answer.

2006-06-15 04:44:44 · answer #5 · answered by ddeity_inc 3 · 0 0

3x-2y=5
-6x+4y=7

Multiply the first equation by 2 and add the 2 equations together:
6x - 4y = 10
-6x +4y = 7
----------------
0 = 17
Which isn't true, so there is no solution.

2006-06-15 06:44:40 · answer #6 · answered by menezes_dean 2 · 0 0

Consider the problem graphically.
Each equation represents a straight line. Two equations have a single solution if the two straight lines intersect at a point.
The two equations you have here represent parallel lines. Therefore they never intersect and your system of equations does not have a solution.

2006-06-15 04:52:08 · answer #7 · answered by loki_knows 4 · 0 0

3x-2y=5
3x=5+2y
let y be 2[imaginary value]
3x=5+2*2
3x=5+4
3x=9
x=3
therefore,if y=2 x=3
like this u can take any value of y and find x

do the same for the next question.

2006-06-15 04:29:23 · answer #8 · answered by sagar420 1 · 0 0

y= 1/2
x=2

2006-06-15 04:24:56 · answer #9 · answered by Anonymous · 0 0

-3/8 =y
17/12 = x

The first guy should get the points. He tought you how to fish; I gave u the fish.

2006-06-15 04:22:59 · answer #10 · answered by bequalming 5 · 0 0

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