how do i write each of the follownig fractions as the products of their prime factors?
5/6
10/25
18/36
15/50
and how do i write the prime factorization of each number and use DIVISION.
18
105
711
2006-06-14 20:48:32 · 6 answers · asked by cocomademoiselle 5 in Science & Mathematics ➔ Mathematics
5/6 = 5/2*3
10/25 = 2*5/5*5
18/36 = 2*3*3/2*2*3*3
15/50 = 3*5/2*5*5
18/2 = 9/3 = 3 so the prime factorization is 2*3*3
105/3 = 35/5 = 7 so the prime factorization is 3*5*7
711/3 = 237/3 = 79 so the prime factorization is 3*3*79
2006-06-14 21:21:50 · answer #1 · answered by cotopaxi 5 · 2⤊ 1⤋
5/6=1*5/2*3=1/2*5/3
10/25=2*5/5*5=2/5*5/5=2/5*1=2/5
18/36=2*3*3/2*2*3*3=2/2*3/3*3/3*1/2=1/2
15/50=3*5/2*5*5=3/2*5/5*1/5=3/2*5
18:2=9, 9:3=3, 3:3=1 => 18=2*3*3
105:3=35, 35:5=7, 7:7=1 => 105=3*5*7
711:3=237, 237:3=79 => 711=3*3*79
2006-06-15 04:10:07 · answer #2 · answered by forever 2 · 0⤊ 0⤋
5/6=5/2*1/3
10/25=2/5*5/5
18/36=2/3 *3/4*3/3
15/50=3/5*5/5*1/2
18=2*3*3
105=3*5*7
711=3* 3* 79
2006-06-15 04:00:22 · answer #3 · answered by iyiogrenci 6 · 0⤊ 0⤋
5/6=5/2/3
10/25=2*5/5/5
18/36=2*3*3/2/3/2/3
15/50=3*5/5/2/5
18=2*3*3
105=3*5*7
711=3*3*79
2006-06-15 11:11:47 · answer #4 · answered by gari 3 · 0⤊ 0⤋
5/(2*3)
(2*5)/(5*5)
(2*3*3)/(2*2*3*3)
(3*5)/(2*5*5)
2006-06-15 03:58:56 · answer #5 · answered by Vivek 4 · 0⤊ 0⤋
hey i am sunidhi and i think that u must ask this question from ur mom or dad or from any of ur friend i hope they will help u
2006-06-15 04:03:06 · answer #6 · answered by cute_sunidhi2003 2 · 0⤊ 0⤋