d
2006-06-14 19:23:17
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answer #1
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answered by F.B.I. 4
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The standard form is (x - h)^2 + (y - k)^2 = r^2
(h,k) is the center
(x - 0)^2 + (y - 0)^2 = 8^2
x^2 + y^2 = 64
ANS : d.) x^2 + y^2 = 64
2006-06-15 06:34:54
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answer #2
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answered by Sherman81 6
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positive. Radius is defined as r. the middle of a circle is (h,ok) The equation of a circle is = (x-h)^2 + (y-ok)^2 = r^2 Given the archives contained in the issue.. center is (0,0), r=15 h=0 ok=0 r =15 We plug contained in the archives. on condition that we are "subtracting" 0, we are able to easily write it as x and y. x^2 + y^2 = 15^2 x^2 + y^2 = 225
2016-11-14 19:25:31
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answer #3
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answered by Anonymous
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the equation is :
x^2+y^2=64
you get this by the following method:
(x-0)^2+(y-0)^2=8^2
=> x^2+y^2=64
2006-06-14 19:25:15
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answer #4
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answered by Anonymous
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(x-0)^2+(y-0)^2=8^2
x^2+y^2=64
The answer is [d].
If ur not able to solve that easy question, then i'll advice u to practice and ask some difficult questions here.
2006-06-14 19:46:51
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answer #5
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answered by Anonymous
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Darn it all, the answer was here a second ago and now it is gone. NOT!!!!!!!!
2006-06-14 19:50:07
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answer #6
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answered by grannywinkie 6
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d
2006-06-14 19:24:46
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answer #7
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answered by big_james_2005 1
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are you trying to get us do your homework for you?
2006-06-14 19:24:03
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answer #8
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answered by akg 3
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it is d hope this isnt a test.....;)
2006-06-14 19:27:21
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answer #9
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answered by sara101usaf 2
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[d]
2006-06-14 19:23:40
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answer #10
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answered by santosh k 3
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