Solving for x
-4(2x-3) = -8x+5
Solving for x
2x+3y = 6
2006-06-14 19:06:59 · 11 answers · asked by Anonymous in Education & Reference ➔ Homework Help
well start by multiplying things out
-8x+12=-8x+5
-8x+8x+12=5
0+12=5
no solution?
2x+3y=6
2x=6-3y
x=6/2-3y/2
x=3-(3/2)y
2006-06-14 19:10:31 · answer #1 · answered by Poutine 7 · 11⤊ 1⤋
multiply -4 through (2x-3)=-8x+12 for the left side...-8x+12=-8x+5...your x's will cancel out ...No Solution
2x+3y=6...x=(6-3y)/2 or x=3-(3/2)y
2006-06-15 02:17:28 · answer #2 · answered by Matt 2 · 0⤊ 0⤋
x=7
2006-06-15 02:16:54 · answer #3 · answered by Anonymous · 0⤊ 0⤋
-4(2x-3) = -8x+5
-8x +12 = -8x+5
-8x + 8x = 5-12
0 = -7 no solution!
I think u have typed it wrong
2x+3y = 6
2x = 6-3y
x = (6-3y)/2
x = (6-3y)/2 ans.
2006-06-15 02:36:01 · answer #4 · answered by Gary 4 · 0⤊ 0⤋
Problem 1 -8x +7 +-8x..........thats as far as i can get
Problem 2 its already solved
I am an A+ math student....but i am only in Pre- Algebra
2006-06-15 02:13:49 · answer #5 · answered by Nick 4 · 0⤊ 0⤋
x=all real numbers as in the equation x cancels out and we can put any value in place of x.
in next equation
2x +3y =6
if we put x=0 than y=2
and if we put y=0 than x=3
so we get infinite set of points like that
and they will occur on a straight line on a graph
these equation can be solved on graph as they would get set of(x,y)
2006-06-15 02:14:32 · answer #6 · answered by KESHAV B 1 · 0⤊ 0⤋
17 and -(3/2)y+3
2006-06-15 02:11:32 · answer #7 · answered by mamimi_18 2 · 0⤊ 0⤋
The first equation is having some problem with it..check it out
2006-06-15 02:14:14 · answer #8 · answered by netizen 2 · 0⤊ 0⤋
the first equation can't be solved .. infact it's wrong.(check it). in the second one just bring the 3y to RHS
2006-06-15 02:13:12 · answer #9 · answered by Anonymous · 0⤊ 0⤋
The first equation seem to be false, no solution-
The math page on this site might help--
2006-06-15 02:17:03 · answer #10 · answered by allaboutfun4 1 · 0⤊ 0⤋