2006-06-14 18:30:51 · 13 answers · asked by Anonymous in Education & Reference ➔ Homework Help
I need to solve for x in both
2006-06-14 18:37:10 · update #1
The equations are wrongor insufficient. Post the correct data if you want me to help/ Alternately, you could also message me.
2006-06-14 18:32:55 · answer #1 · answered by Rakesh A 4 · 0⤊ 0⤋
The first equation is wrong .. since if that is true then 15 =5 which is obviously not true.
As for the second one you will need one more equation to find the value of the varables x and y. since there are 2 unknown variables you will need 2 questions.
2006-06-20 21:10:42 · answer #2 · answered by Ravi 3 · 0⤊ 0⤋
For 2x + 3y = 6 ; get the value of (y) first;
3y = 6 - 2x
3y / 3 = (6 - 2x) / 3
y= ( 6 - 2x ) / 3
Then substitute it:
2x + 3y = 6
2x + 3 [ (6-2x) / 3 ] = 6
I'm sure you can continue from here......
2006-06-15 07:18:46 · answer #3 · answered by Tungak 1 · 0⤊ 0⤋
-4(2x - 3)=8x + 5
-8x + 12 = 8x + 5
16x = 7 (add 8x & -5 to both sides of equality)
x = 7/16
PUT THIS VALUE OF x IN other equation and you will find the value of y. write to me if you need furthur assistance at sudhanshu.varma@yahoo.co.in
2006-06-14 18:38:40 · answer #4 · answered by sonu 2 · 0⤊ 0⤋
-4(2x-3)=-8x+5
Distribute the -4
-8x+12=8x+5
Subtract 5
-8x+7=8x
Add 8x
7=16x
x=2.2857
2x+3y=6
no way to solve unless you know the value of X or Y.
Sorry.
2006-06-14 18:35:58 · answer #5 · answered by Anonymous · 0⤊ 0⤋
Cannot solve any of the equations. Gottagetit, in the second line of your workout, you missed the (-) next to the 8 after the = sign.
2006-06-14 18:40:28 · answer #6 · answered by RG 2 · 0⤊ 0⤋
that your homework ? LOL
i think u got to do -4 times 2 then -4 times -3
then with the other one 6 times 2 then 6 tiems 3 ..... try that and figue it out
2006-06-14 18:32:28 · answer #7 · answered by Mysteriousoso 2 · 0⤊ 0⤋
x=all Real numbers
as x cancels so we put any value of x
in the equation.
next equation we can get value of x, wrt to y
we will get set of values
2x+3y=6
put, x=0,y=2
put,x=3,y=0
ploting this on a graph we will get a straight line
having infinite set of values
2006-06-14 19:07:09 · answer #8 · answered by KESHAV B 1 · 0⤊ 0⤋
8x^3* 2x^5 ----------------- 4x^6 cancel the elementary component of four between the numerator and denominator 4*4x^8 ----------- = 4x^6 4x^8 -------- x^6 use the quotient rule for exponents: x^8/x^6 = x^(8-6) = x^2 the basically suited answer is 4x^2
2016-12-08 09:19:39 · answer #9 · answered by Anonymous · 0⤊ 0⤋
Hmmm.. what are you solving for? Need to state the question you were asked.
2006-06-14 18:35:20 · answer #10 · answered by Keith H 2 · 0⤊ 0⤋