x^2-9x-4=6 quadratic equations by factoring........please help....?

Answer 1

x^2-9x-10=0

x^2 +(-1 +10)x -10=0

x^2 -x +10x -10=0
x(x-1) +10(x-1)=0

(x+10)(x-1)=0
thus x=10 , -1

Answer 2

First, bring the 6 onto the left side of the equation. You get
x = x^2 - 9x - 10
Now you factor (or use the quadratic formula)
Since the 10 is negative, the two numbers have different signs. Since 9 is negative, the number with the higher absolute value is negative. The two numbers add to -9 and multiply to -10.
10....10 and 1, 5 and 2...
(x - 10)(x + 1) = 0

Now either
(x - 10) = 0
x = 10
or
(x + 1) = 0
x = -1

The solution set is {-1, 10}

Answer 3

To solve a quadratic by factoring, arrange it to look like

A(x2) + B(x) + C = 0

You want to find factors so that

(px + q) (rx +s) = A(x2) + B((x) + C

This means that:
A = rp
B = ps + qr
C = qs

Since in the example you give, A = 1, we want p = r = 1
B = s + q
C = qs

thus: 1(x2) + (-9)(x) + (-10) = 0

so we want numbers that add to - 9 and multiply to - 10

factors of 10 would be either 2 and 5 or 1 and 10

Since we want opposite signs (multiply to NEGATIVE 10), our choices would be
(i) 2 -5
(II) -2 5
(III) 1 -10
(iv) -1 10

We want the pair that adds to -9. Clearly this is (iii).

This method works best when the answers (roots) are rational. If none of these possibilities work, then the roots will be irrational and will take the form U + sqrt V; U - sqrt V.
Then we will want
= 1(x2) + (B/A)(x) +(C/A)
B/A = (U + sqrt V) + (U - sqrt V) = 2U
C/A = U*U - V (following the pattern = y*y -z*z)

which leads to the quadratic forumula.

Answer 4

Move 6 onto the other side first.

x^2 - 9x - 10 = 0

Now, using the quadratic formula, we get this:

x = 9 +- sqrt(81 - 80) / 2

So x equals either 5 or 4.

Answer 5

Rearrange: x^2 - 9x - 10 = 0.

Then (x - 10)(x + 1) = 0

x= 10; x= -1.

Answer 6

x^2-9x-4-6=0

x^2-9x-10=0

the product is -10
the sum is -(-9)=9

(x+1)(x-10)=0
To solve this equation equate each factor to zero.
Because 0*0=0
x+1=0
x=-1 (the first root)

x-10=0
x=10 (the second root)

Answer 7

x^2-9x-4-6=0
x^2-9x-10=0 -10= -2*5 or 2*-5 or -1*10 or 1*-10
using 1&-10 -9=1+(-10)
therefore
(x-10)*(x+1)

Answer 8

x^2 - 9x - 10 = 0
(x + 1)(x - 10) = 0
x = 10, -1

Answer 9

x^2 - 9x - 10 = 0

METHOD 1: Factoring
(x - 10)*(x + 1) = 0
x = {-1, 10}

METHOD 2: Quadratic Formula
x = (9 ± sqrt(9*9 - 4(-10)1))/2
x = (9 ± sqrt(81 + 40))/2
x = (9 ± sqrt(121))/2
x = (9 ± 11)/2
x = {-1, 10}

Answer 10

element: x^2 + x - one million on account that this equation would not element gently, you will might desire to apply the Quadratic formulation to locate the value(s) of x. verify out your equation like this: ax^2 + bx - c meaning: a = one million b = one million c = -one million Plug it into the Quadratic formulation: x = (-b +or- squarerootof(b^2 - 4(a)(c)) / (2a) x = (-one million +or- sqrt((one million)^2 - 4(one million)(-one million)) / 2 x = (-one million +or- sqrt(one million - -4)) / 2 x = (-one million +or- sqrt(5)) / 2 ^on account which you are able to no longer take the sq. root of 5 (it comes out as a decimal), it particularly is so some distance as you are able to take it. basically situation left to do is divided the + or - by utilising making 2 equations to that end, x = (-one million + sqrt(5)) / 2 AND x = (-one million - sqrt(5)) / 2 or x = .sixty two x = -one million.sixty two after plugging in all of the above x values back into the equation (plugging .sixty two and -one million.sixty two into the unique equation, attempting to locate one which will make the equation equivalent 0), you will locate that the two solutions artwork. x = -one million.sixty two and .sixty two