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I got a 94 on an Algebra test and the only question which I totally did not get was:

8h/ + h+1/
h^2-49 7-h

Now I'm studying for my final and I would like to know how to do this problem. Can somebody please show me how to do it? I got as far as factoring h^2-49 into (h+7)(h-7).

Thanks in advance.

2006-06-14 06:56:16 · 3 answers · asked by mbtafan 3 in Science & Mathematics Mathematics

3 answers

8h/(h^2-49) + (h+1)/(7-h)

= 8h/(h+7)(h-7) -(h+1)/(h-7)

= (8h - (h+1)*(h+7) )/(h-7)*(h+7)

= 8h - h^2-8h-7/(h^2-49)

= -(h^2+7)/(h^2-49)

You sure you got a 94 on that test ???????????????

2006-06-14 07:03:14 · answer #1 · answered by ag_iitkgp 7 · 2 0

((8h)/(h^2 - 49)) + ((h + 1)/(7 - h))
((8h)/(h^2 - 49)) + ((h + 1)/(-h + 7))
((8h)/(h^2 - 49)) + ((h + 1)/(-(h - 7))
((8h)/(h^2 - 49)) - ((h + 1)/(h - 7))
((8h)/((h - 7)(h + 7))) - ((h + 1)/(h - 7))
Multiply everything by (h - 7)(h + 7)
(8h - ((h + 1)(h + 7)))/((h - 7)(h + 7))
(8h - (h^2 + 7h + h + 7))/((h - 7)(h + 7))
(8h - (h^2 + 8h + 7))/((h - 7)(h + 7))
(8h - h^2 - 8h - 7)/((h - 7)(h + 7))
((8 - 8)h - h^2 - 7)/((h - 7)(h + 7))
(-h^2 - 7)/((h - 7)(h + 7))
(-h^2 - 7)/(h^2 - 49)

2006-06-14 16:05:58 · answer #2 · answered by Sherman81 6 · 0 0

why dont you rewrite it. It doesnt make sense as written

2006-06-14 07:03:41 · answer #3 · answered by Scott R 6 · 0 0

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