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2006-06-13 16:17:24 · 7 answers · asked by mike s 1 in Sports Baseball

Anon 28 got the answer correctly, perfect description

2006-06-13 16:30:10 · update #1

7 answers

Six. 1) Hit, pick off. 2) Hit, pick off. 3) single. 4) single (1st & 2nd) 5) single (bases loaded). 6) batted ball strikes runner, runner is called out. The play is at the discresion of the official scorer as to whether to call it a hit or an out.

2006-06-13 16:21:00 · answer #1 · answered by Anon28 4 · 7 2

I believe the answer is 6. Get three singles to load the bases. Then have the next three hitters hit the runner at third in fair territory with a batted ball. The runner is out but I believe the batter is credited with a hit so you could have six hits without a run.

2006-06-13 23:21:40 · answer #2 · answered by doubledown 2 · 0 0

I'd say, five. If you lead the inning off with two singles, but the runner only advances to second on the second hit. Then you hit another single and the runner on third gets thrown out at home with the runner on first only advancing to second. Do that two more times and you get five singles and no runs.

2006-06-13 23:24:17 · answer #3 · answered by southfloridamullets 4 · 0 0

6, get three people on base and each of the next 3 hitters, hit the ball on the ground and the infielder gets the player out at home

2006-06-13 23:23:57 · answer #4 · answered by bballmsm1021 2 · 0 1

Five, three straight singles to load the bases, then a double play, to clear two of the bases, and then two more singles to load them up again.

2006-06-13 23:24:51 · answer #5 · answered by matttitch57 1 · 0 0

3 times because you can hit around three times and make all of the outs on the bases

2006-06-13 23:23:02 · answer #6 · answered by Nate DOGG 1 · 0 1

7 with all hits being singles and runners getting thrown out trying to steal home

2006-06-13 23:21:40 · answer #7 · answered by phylerphan 1 · 0 1

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