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2006-06-13 16:01:35 · 7 answers · asked by missnikki630 1 in Science & Mathematics Mathematics

You can use the numbers multiple times
Example:2222 1111 1122

2006-06-23 15:49:37 · update #1

7 answers

If I did the math right there are ten numbers 0,1,2,3,4,5,6,7,8,9

They must be put in a group of four. Thats 10 to the fourth power. So thats about ........ 10,000 possible combonations. If your asking the possible combonation to a lock....... Well good luck unloking it.

2006-06-25 14:56:56 · answer #1 · answered by Anonymous · 1 0

4

2006-06-13 23:07:19 · answer #2 · answered by anthony b 1 · 0 0

The question, as stated, asks for number combinations--which suggests that 1234 and 1342 would be considered the same combination. There is also no reason to believe that the values selected cannot begin with 0.

To ask the question another way--if I am understanding you correctly--you have ten numbered slips of paper in a hat and you want to draw out four of them. If you then place the four drawn slips of paper in ascending order, how many different results could you obtain?

The answer is a combination of four items drawn from 10:
n!/[(n-r)!r!]
= 10!/((10-4)!(4!]
= 10!/(6!4!)
= (10x9x8x7x6x5x4x3x2x1)/(6x5x4x3x2x1x4x3x2x1)
= (10x9x8x7)/(4x3x2)
= 210.

An earlier answer suggested 604,800, but that answer used the wrong formula for a permutation. A permutation is:
n!/(n-r)! = 10!/(10-4)! = 10!/6!
= (10x9x8x7x6x5x4x3x2x1)/(6x5x4x3x2x1)
= 10x9x8x7 = 5,040
The solver suggested 10x9x8x7x6x5x4, but this is incorrect.

But the answer to your question is 210.

2006-06-23 18:13:24 · answer #3 · answered by tdw 4 · 0 0

For this you use combinatorics. You are choosing groups of 4 out of a pool of 10 digits. Note that order is important: 1234 is not the same as 2134.

So this means there are a total of 10!/4! combinations, so
10x9x8x7x6x5x4=604800 possible combinations

2006-06-13 23:05:33 · answer #4 · answered by Yo 2 · 0 0

you didn't say if we could use multiples of any number.. if you can.. you would have all numbers from 0000 to 9999 or 10,000 numbers.. if not... then you have a choice of 10 numbers for the first, 9 numbers for the second, 8 numbers for the third, and 7 numbers for the fourth.. or 10*9*8*7 = 5040 numbers

2006-06-23 22:16:22 · answer #5 · answered by ♥Tom♥ 6 · 0 0

Assuming the number does not starts with 0
There will be 9000 four digited number.

2006-06-14 01:50:12 · answer #6 · answered by partha_mj 2 · 0 0

1259
2395
5629
7264
7346
1234
4234
5435
0

2006-06-13 23:17:22 · answer #7 · answered by Anonymous · 0 0

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