A line with slope 2 passes through the origin.What is a point on the line?

Answer 1

you can use the y=mx+b formula for a line.

y is the y-coordinate of a point

m is the slope, x is the x-coordinate of a point

b is the y-intercept (where the line touches or intercepts the y-axes).

since you know the y intercept of the line (passes through origin, so it's 0), the value of b would be 0 and you also know the slope of the line, which is two, the equation for the line would look like this.

y=2x + 0 or y=2x

a point on the line would have coordinates that would fit the equation ---- y has to be two times x; x has to be 1/2 of y.

here are some points on this line: (0,0), (1,2), (-1,-2), (2,4), (-2,-4).

hope that helped :)

Answer 2

(1,2) or (2,4) The line has a slope of 2, which is 2/1 for rise over run. Count up to from the origin two and over one. Use can use that method to find multiple points on the line starting from any known point on the line.

Answer 3

Begin by writing the line's equation in slope intercept form

y = mx + b

m = slope = 2
b = y-intercept = 0,

So, the equation is y = 2x + 0.
Now, just substitute any value for x and you will find the y-value that corresponds with it.

Some sample values are
(-2, -4), (-1, -2), (0, 0), (1, 2), and (2, 4)

Answer 4

Try using the slope intercept form. the intercept is (0,0) , and the slope is 2.
the equation is: y-0 / x-0 = 2
therefore: y = 2x
put any value for x to find the corresponding value of y.
e.g. (1,2), (2,4)......

Answer 5

(1, 2)

Answer 6

y = mx + b; b=0; m=2
y = 2x

Just plug in any value for x and solve for y to get a point.
Examples: (0,0); (1,2); (3,6); (-2,-4)

Answer 7

Well, you could start with the origin!

Answer 8

I agree with (1,2)

Answer 9

(1,2)(2,4)(3,6)(4,8)(5,10)(6,12)(7,14)(8,16)(9,18)(10,20)
This one has an easy pattern ;)