I'll give you a proof:
Start with the identity:
-20 = -20
Express both sides in slightly different, yet equivalent ways:
16 - 36 = 25 - 45
Factor both sides:
4^2 - 4 x 9 = 5^2 - 5 x 9
Complete the square by adding 81/4 to both sides:
4^2 - 4 x 9 + 81/4 = 5^2 - 5 x 9 + 81/4
Factor both sides again:
( 4 - 9/2 )^2 = ( 5 - 9/2 )^2
Take the square root of both sides:
4 - 9/2 = 5 - 9/2
Cancel the common factor:
4 = 5
And since 2 + 2 = 4:
2 + 2 = 5
Q.E.D. (But obviously there is an error in my proof... can you find it?) This probably isn't the "proof" you were looking for, but it does show 2 + 2 = 5...
Edit: Okay there was a request to know where the error lies. It's in the step where we take the square root of both sides. Note that (x)^2 = (-x)^2, but the square root of both sides is not necessarily equal.
2006-06-13 13:51:36
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answer #1
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answered by Puzzling 7
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No, no rounding up is required.
Here's how it works: (p.s. I gave this proof to five people already)
Take two constants, a and b. Take them to be 2, for instance.
Now, multiply both sides by b:
ab = b²
Subtract a² from both sides:
ab - a² = b² - a²
Factor both sides:
a(b-a) = (b+a)(b-a)
Divide both sides by (b-a):
a = a+b
Now, subtract a from both sides:
0 = b
Therefore:
0 = 2
Now, if you multiply both sides by 2.5 at this point, you get:
0 = 5
So, 2+2=5, which is true, because 0+0=0. Get my logic?
P.S. This proof is... not EXACTLY accurate. There's something wrong with it. It's the part where you divide by (b-a). This equals zero, and you can't exactly divide by zero...
Ok, bandf, I give up. You've hidden your error quite well. What is it?
2006-06-13 13:54:20
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answer #2
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answered by Anonymous
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ive never seen a 2+2=5 proof, but i do know the 1=0 proof, and that only works b/c the constant of integration is left out
2006-06-13 13:06:39
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answer #3
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answered by ap chem student 2
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Steven F is Right, and that is one of the reasons you cant divide by zero. There are some things in math that just aren't allowed.
It just like logic. lets say there are a group of kids. They vote on whether 2+2=5
23 vote yes
7 vote no
does this make it logically true? No, this is known as appealing to the majority, and is a logical fallacy.
Same with math. You saw that proof because someone did an illegal operation in their logical thinking of math.
:-)
-Nick
2006-06-13 13:00:12
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answer #4
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answered by odiousmanilla 2
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there is an unknown # that is 1 and makes it 5
2006-06-13 12:57:00
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answer #5
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answered by markastenson 2
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"2" is a symbol that can stand for any amount. It's like a variable. We just use it to stand for the value of two. Suppose we replace "2" with x and solve
2 + 2 = 5
x + x = 5
2x = 5
x = 2.5
So yes it is possible if the symbol "2" stands for the amount of "two and one-half"
2006-06-13 13:19:27
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answer #6
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answered by Zαrα Mikαzuki 6
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Start with a=b.
Some where onlng the ling divide by (a-b).
Prove a=2b.
Since a=b, this porves 1=2.
Division by 0 (a-b) is undefined.
You can prove anything.
I forgot the rest.
2006-06-13 12:54:23
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answer #7
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answered by STEVEN F 7
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You'd have to have other numbers though wouldnt you? It can't just be 2+2=5. You need other numbers or signs or something.
Strange.. but pretty cool.
2006-06-13 13:31:26
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answer #8
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answered by Anonymous
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The second 2 is pregnant. Look closely. She's starting to show.
2006-06-13 13:29:36
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answer #9
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answered by Sleek 7
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It can't be done. People who do this crap are just very tricky. Math does not lie.
2006-06-13 12:57:28
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answer #10
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answered by Levi E 3
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