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(3y-1) + 2y = 9
5y - 1 = 9
5y = 10
y=2

3(2)-1 =x
6-1=x
5=x

2006-06-13 12:46:22 · answer #1 · answered by unc95kelly 3 · 0 0

2

2006-06-13 20:36:05 · answer #2 · answered by Joyous 2 · 0 0

y = 2
x = 5

Here's how:
Substitute the first equation into the second equation. This would be simpler than substituting the second equation into the first equation - because the first equation is given in terms of the x alone:
so - replacing the x in the second equation for "x=3y-1" gives you this:
3y - 1 + 2y = 9
Now you have only one letter to deal with for now:
Rearrange the equation so that all the letters are on one side, and all the numbers are on the other side:
3y + 2y = 9 + 1
(the 1 becomes + because it was moved to the other side of the equation)
Now, simplify:
3y + 2y = 5y and
9 + 1 = 10
So now you have:
5y = 10
In order to isolate the y, divide both sides of the equation by 5:
(5/5)y = 10 / 5
Solve the problem, and now you have your y!
y = 2

In order to now find the x, replace the y in the original first equation with 2:
x = 3(2) - 1
so -
x = 6 - 1
x = 5

There, you have your answer!

2006-06-13 19:59:47 · answer #3 · answered by hannahbeen 1 · 0 0

The first equation gives x=3y-1
Substitute 3y-1 for X in the second equation
So:
3y - 1 + 2y = 9
Group like terms
5y -1 = 9
Add 1 to each side
5y = 10
Divide each side by five
y = 2

We now have:
X = 3Y-1
Y = 2
Plug 2 in for Why and you get:
X = 3(2) - 1
X = 5

2006-06-13 19:48:45 · answer #4 · answered by jane9715 2 · 0 0

y=2

2006-06-13 19:46:09 · answer #5 · answered by Thoma D 1 · 0 0

x= 3y - 1
x + 2y = 9
(3y -1) + 2y = 9
5y - 1 = 9
5y = 10
y = 2

2006-06-13 19:48:10 · answer #6 · answered by C.W. 2 · 0 0

3y -1 +2y = 9
5y = 10
y = 10/5 or 2
SO
x = 3(2) - 1
x = 6 -1
x = 5

2006-06-13 19:50:30 · answer #7 · answered by missye20032002 1 · 0 0

equation 1: x=3y-1
equation 2: x+2y=9
First replace the x in equation 2 with the 3y-1 from the first equation since it is equal to x.
that gives you this equation:
3y-1+2y=9
then you simplify:
5y=10
y=2

2006-06-13 19:50:08 · answer #8 · answered by jtiernan07 2 · 0 0

sub x=3y-1 in the 2nd equation
3y-1+2y=9
5y-1=9
5y=10
y=2

2006-06-16 01:49:06 · answer #9 · answered by pavitra 2 · 0 0

wr have to equation
X=3y-1
x+2y=9
we just replece first equation tosecound
(3y-1)+2y=9
3y+2y=9+1
5Y=10
Y=10/5
Y=2

2006-06-13 20:12:25 · answer #10 · answered by mohaqiqjh 1 · 0 0

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