2006-06-13 12:00:01 · 7 answers · asked by drunkenmasta_fei 2 in Science & Mathematics ➔ Mathematics
f(x) = 2x + 4
f(3x) = 2*3*x + 4 = 6*x + 4
3*f(x) = 2*3*x + 3*4 = 6*x + 12
f(3x) - 3*f(x) = (6x + 4) - (6x + 12) = 4 - 12 = -8
2006-06-13 12:04:44 · answer #1 · answered by professional student 4 · 0⤊ 0⤋
First, substitute the (3x) everywhere that there is an (x), and then multiply the 3 by f(x); remember f(x) is equal to 2x+4
2(3x)+4 - 3(2x+4)
6x+4-6x-12
-8 is the answer
2006-06-13 12:07:10 · answer #2 · answered by pilotmanitalia 5 · 0⤊ 0⤋
f(x) = 2x + 4
f(3x) = 2(3x) + 4 = 6x + 4
3(f(x)) = 3(2x + 4) = 6x + 12
f(3x) - 3f(x) = 6x + 4 - (6x + 12) = 6x + 4 - 6x - 12 = -8
ANS : -8
2006-06-13 13:03:47 · answer #3 · answered by Sherman81 6 · 0⤊ 0⤋
f(3x)= 2(3x) + 4 = 6x +4
3f(x)= 3(2x + 4) = 6x +12
therefore, f(3x) - 3f(x) = -8
2006-06-13 12:06:25 · answer #4 · answered by Vision 2 · 0⤊ 0⤋
f(3x)-3f(x)=2(3x)+4-3[2x+4]
=6x+4-6x-12=-8
2006-06-13 12:16:51 · answer #5 · answered by Dr JPK 2 · 0⤊ 0⤋
f(3x) = 6x + 4
3f(x) = 6x + 12
f(3x)- 3f(x)= (-8)
2006-06-13 12:03:44 · answer #6 · answered by C.W. 2 · 0⤊ 0⤋
-8
2006-06-13 12:04:44 · answer #7 · answered by wazzzzzzzup 2 · 0⤊ 0⤋