Find the value of x so the line that passes through (x, 6) and (10,-3) is parallel to the line that passes thr

Answer 1

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Answer 2

Lets say you have another set of coordinates

(x1,y1) and (x2,y2)
m = (y2 - y1)/(x2 - x1)

for 2 lines to be parallel, they must have the same slope

(x,6) and (10,-3)
m = (-3 - 6)/(10 - x)
m = (-3 + (-6))/(10 - x)
m = (-9/(10 - x))

so now to find the value of x, set the 2 slopes equal to each other

(y2 - y1)/(x2 - x1) = (-9/(10 - x))

Cross multiply

-9(x2 - x1) = (y2 - y1)(10 - x)

divide both sides by (y2 - y1)

(-9(x2 - x1))/(y2 - y1) = 10 - x

subtract 10 from both sides

-x = ((-9(x2 - x1))/(y2 - y1)) - 10

divide both sides by -1

x = ((9(x2 - x1))/(y2 - y1)) + 10

Answer 3

passes through..what...we can help you out if you tell us

Answer 4

this problem is impossible to solve unless you finish typing it or pasting it.