2006-06-13 07:02:36 · 4 answers · asked by veluguri 1 in Science & Mathematics ➔ Mathematics
3x-4y-1=0
distance=4.8
2006-06-13 07:06:30 · answer #1 · answered by sammy 3 · 1⤊ 0⤋
4x+3y+6=0 is equal to 3y= -4x-6, which is in turn equal to
y=-4/3x-2. You then find the perpendicular line by taking the opposite reciprocal of the slope described as -4/3. You get 3/4. So far your equation is y=3/4x+?. To find the ?, which represents the y-axis intercept, you use the equation y-y1=m(x-x1), where m=slope of the line.
y-2=3/4(x-3)
y-2=3/4x-9/4 multiply both sides by 4 to simplify.
4y-8=3x-9 set the equation equal to zero.
4y-3x+1=0
Because the equation is linear with two variables, the line is interminable (will go on forever). Thus all solutions are at the same time correct (if they satisfy the equation) and incorrect because the length of the line is indeterminable.
2006-06-13 07:31:34 · answer #2 · answered by Janet A 2 · 0⤊ 0⤋
Janet is right.
The quick way to get the equation of the perpendicular is to use the basic straight line equation: Y = mX which goes thru the origin. The line not thru the origin is (Y - h) = m(X - k). In this case (Y-2) = (3/4)(X - 3).
That's the equation and at this point you'd have the right answer on your paper. The rest is simple algebra to put it into the form the question asks for.
2006-06-13 08:14:16 · answer #3 · answered by Anonymous · 0⤊ 0⤋
(4*3+3*2+6)/sqrt(4*4+3*3) = 24/sqrt(25) = 24/5
2006-06-13 07:06:43 · answer #4 · answered by ag_iitkgp 7 · 0⤊ 0⤋