Consider a mixture of air and gasoline vapor in a cylinder with a piston. The original volume is 60. cm3. If the combustion of this mixture releases 830 J of energy, to what volume will the gases expand against a constant pressure of 670 torr if all the energy of combustion is converted into work to push back the piston?
2006-06-13 05:25:24 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
work = -PdV = -P(V(1)-V(2))
w=830joules, P=670torr, V(1)=60cm(cubed), V(2)=n
830 = -670(60-n) = - 40200 + 670n
830 + 40200 = 670n - 40200 + 40200
41030 = 670n
41030/670 = 670n/670
61.2388 = n = V(2)
PLUG INTO TOP EQUATION (w=-PdV) to check answer...
2006-06-13 06:08:06 · answer #1 · answered by Anonymous · 1⤊ 0⤋
Let final volume be v
So, P(v-60) = 830
or v = 830/670 + 60
2006-06-13 05:30:28 · answer #2 · answered by ag_iitkgp 7 · 0⤊ 0⤋