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choices and their sides

1. 22cm, 14cm, 7cm

2. 18cm, 7cm, 12c

3. 14cm, 22cm, 6cm

2006-06-12 16:10:44 · 12 answers · asked by Anonymous in Science & Mathematics Mathematics

12 answers

2 is a real triangle.

In 1 & 3, the short sides add up to less than the long side and, therefore, could not possibly meet.

2006-06-12 16:14:37 · answer #1 · answered by tiffany 6 · 0 0

3

2006-06-12 16:20:55 · answer #2 · answered by Anonymous · 0 0

Only item 2. is a REAL triangle.


1. 14+7 = 21 < 22 (not a triangle)

2. 12+7 = 19 > 18 (real triangle)

3. 14+6 = 20 < 22 (not a triangle)

2006-06-12 17:01:39 · answer #3 · answered by ideaquest 7 · 0 0

If the sum of any two sides of a triangle is greater than or equal to the remaining side, it is NOT a triangle.

1. Yes, it's a triangle.
2. No, 7 + 12 = 19, 19 > 18
3. Yes

2006-06-12 16:35:00 · answer #4 · answered by Chie 5 · 0 0

22+14>7
22+7>14
14+7<22

7+18>12
18+12>7
12+7>18

14+22>6
22+6>14
14+6<22

second one sorry i put in the wrong number for some reason check ya later ♥

2006-06-12 17:23:07 · answer #5 · answered by ♥ The One You Love To Hate♥ 7 · 0 0

None of them. A true triangle has 120 degrees between each point. There is a name for these type of forms, but I've forgotten the name. I've been out of school almost 50 years.

2006-06-12 16:20:17 · answer #6 · answered by Anonymous · 0 0

18cm.,7cm,12cm form a real triangle as the sum of any 2 sides is always greater than the 3rd side &difference of any 2 sides is always less than 3rd side.

2006-06-12 16:44:35 · answer #7 · answered by Sindhu 2 · 0 0

2.

For any triangle with sides A, B, and C, in descending order. A must be less than B + C.

2006-06-12 16:20:55 · answer #8 · answered by Anonymous · 0 0

only 3 is NOT a REAL triangle.
1 and 2 are

2006-06-12 16:23:15 · answer #9 · answered by Morkeleb 3 · 0 0

number two, as long as "12c" is supposed to be "12cm." the sum of two sides must be greater than the third, and in number one, 14+7<22, and in number three, 14+6<22.

2006-06-12 16:21:15 · answer #10 · answered by petestokalovich 2 · 0 0

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