ok i don't understand how this works.
-5x+1>(or equal to) 1
when i subtract the 1 from both sides i get 0, so is it -5x>(or equal to) 0? is that right so far?
and also 6+3x<(or equal to) 5, would the answer be x>(or equal to 1/3) ?
2006-06-12 16:00:46 · 10 answers · asked by Stephanie 3 in Science & Mathematics ➔ Mathematics
thanks for the help
2006-06-12 16:07:42 · update #1
you are right about the first one -5x>=0 or 5x<=0 or x<=0.
The second one is a little off.
It should be 3x<=-1 or x<=-1/3
the 1/3 is negative.
2006-06-12 16:03:23 · answer #1 · answered by Eulercrosser 4 · 0⤊ 0⤋
The answer to both is YES. When you subtract 1 from both sides, you get 0 on the right. In the second problem, x is greater than or equal 1/3 b/c you have to switch the inequality sign when dividing with a negative number.
2006-06-12 23:10:40 · answer #2 · answered by Ace Kinkaid 2 · 0⤊ 0⤋
-5x + 1 > = 1
=> - 5x >= 0
=> 5x >=0
=> x >=0
and the other one;
6 + 3x <=5
=> 3x <= -1
=> x <= -1/3
2006-06-13 02:15:04 · answer #3 · answered by Anonymous · 0⤊ 0⤋
the first one is correct and, like many have said, you can go one step futher and make it x<=0.
I might be assuming incorrectly but it looks like for the second one you tried to get rid of the negative sign by multiplying be a -1 and switching the < to a >, but that would only move the negative sign to the other side, infront of the x. If this was the case you forgot the negtive sign infront of the x. It would read -x>= 1/3.
Even if I am incorrect in my assumption the equation should read x<= -1/3.
2006-06-13 07:43:26 · answer #4 · answered by rikki71685 1 · 0⤊ 0⤋
actually you can go one step further in the first one and state that x<=0 since you can divide both sides by -5 but when you multiply or divide by a negative number, the sign switches so be careful.
in the second case, you were right except for the signs. It will not switch since both sides are being multiplied by a positive number. i.e. x<=(-1/3)
2006-06-12 23:06:46 · answer #5 · answered by Morkeleb 3 · 0⤊ 0⤋
The first one is right so far, then divide by -5 and you get 0.
the second one is right except it's -1/3 (negative one third)
2006-06-12 23:04:37 · answer #6 · answered by mama3x 3 · 0⤊ 0⤋
-5x >= 0 is right.
Ok, x <= -1/3 (negative third)
2006-06-12 23:06:22 · answer #7 · answered by Chie 5 · 0⤊ 0⤋
yes thats right so far
this might just be a typo, but the second one should be x<(or=to)1/3 you dont have to switch the sign because youre not dividing by a negative number
2006-06-12 23:03:54 · answer #8 · answered by lebeauciel 3 · 0⤊ 0⤋
6+3x<(or equal to)5,we can make change
3x<(or equal to)5-6
3x<(or equal to)-1
so, x<(or equal to} -1/3
that's all
2006-06-12 23:14:12 · answer #9 · answered by Dark Angel 5 · 0⤊ 0⤋
believe it or not, you are completely right
2006-06-12 23:03:20 · answer #10 · answered by eddie_287 2 · 0⤊ 0⤋