What is the volume of a soap bubble that has a surface area of 12 square cm?

Answer 1

ok, a soap bubble is a sphere, the SA of a sphere is 4 pi r^2
and the volume is 4/3pi r^3

so you have
12 = 4pir^2
3=pir^2
sqrt(3/pi) = r

plug that into the volume equation

Answer 2

soap bubble is a sphere and so as we know the surface area of a sphere = 4 pi r^2
and its volume = 4/3 pi r^3
given is the surface area which is 12cm^2
therefore, 12 = 4 pi r^2
=>r^2 = (12)/(4 pi)
=>r^2 = 3/pi
=>r^2 = 0.9554 cm^2
=>r = sqrt 0.9554cm^2
=>r = 0.9774 cm

now the volume = 4/3 pi r^3
= 1.333 * 3.14 * (0.9774)^3
= 3.908 cm^3

Answer 3

since soap bubble is a sphere,calculate the radius using the formula
4*pi*radius square =12= surface area
radius=root of 21/22

subsitute th value of radius in equation of volume of sphere

4/3*pi*radius cube=volume of sphere claculate the answer

Answer 4

The radius of the bubble is sqrt(3/pi) or 0.98 cm

The volume of the bubble is 4 times sqrt(3/pi) or 3.90882009522335937269107...
...69827068 cubed cm

Answer 5

S = 4 Pi r^2 = Pi d^2
V = (4 Pi/3)r^3 = (Pi/6)d^3

12 = 4pi * r^2
3 = pi * r^2
(3/pi) = r^2
r = sqrt(3/pi)
r = (sqrt(3pi))/pi

V = (4 Pi/3)r^3
V = (4pi/3)((sqrt(3pi))/pi)^3
V = 3.90882
or
V = about 3.91cm^3