Factorize:
35x^3 + 79x^2 - 75x +9
2006-06-12 06:38:34 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
(x+3) (5x-3) (7x-1)
You can do this manually by figuring out the factors of 35 and 9.
For 35: {1, 5, 7, 35, -1, -5, -7, -35)
For 9: {1, 3, 9, -1, -3, -9)
I started assuming that (x + n) would be a factor. I tried (x + 1), (x - 1), then (x + 3).
If you do long division, you get:
(x + 3) ( 35x^2 - 26x^2 + 3)
Then you just repeat the process for ( 35x^2 - 26x^2 + 3)... you need factors of 35 and factors of 3 that will add up to -26.
-3 x 7 = -21 and -1 x 5 = -5, so (5x - 3)(7x - 1) works.
That gives the final answer of:
(x+3) (5x-3) (7x-1)
2006-06-12 06:56:27 · answer #1 · answered by Puzzling 7 · 0⤊ 0⤋
42875 + 6241 - 75 + 9 = 49050 (just a guess?!?!)
2006-06-12 13:49:31 · answer #2 · answered by lala 2 · 0⤊ 0⤋
wow im not even gonna try that
2006-06-12 13:41:57 · answer #3 · answered by no name 3 · 0⤊ 0⤋