Let ABCD be a square whose side is 8 units. Find the length of diagonal AC to the nearest tenth.
2006-06-12 03:01:41 · 5 answers · asked by georgia_gal461 1 in Education & Reference ➔ Homework Help
Pythagoras:
AC squared = AB squared + BC squared
Therefore
AC = square root of quantity (AB^2 + BC^2)
You can do the math.
2006-06-12 03:07:17 · answer #1 · answered by williegod 6 · 6⤊ 0⤋
AC = 8 * sqaure root 2
= (about) 11.31
2006-06-12 03:24:13 · answer #2 · answered by ellenangel364 3 · 0⤊ 0⤋
8 sqrt 2, or 11.3 units
2006-06-12 06:25:14 · answer #3 · answered by jimbob 6 · 0⤊ 0⤋
8*â(2)=11.313708498984760390413509793678, which is approximatley 11.3 units.
2006-06-12 03:48:06 · answer #4 · answered by anonymous 3 · 0⤊ 0⤋
8*1.414 = 11.312
11.3 units
2006-06-12 03:05:42 · answer #5 · answered by suddenflirt 2 · 0⤊ 0⤋