find the product
(y+4)(x^2 y+2x^2-3)
2006-06-12 01:27:49 · 15 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
x^2y^2 + 2x^2y - 3y + 4x^2y + 8x^2 -12
x^2y^2 + 6x^2y + 8x^2 - 3y - 12
2006-06-12 03:48:31 · answer #1 · answered by jimbob 6 · 1⤊ 0⤋
(y+4)(x^2 y+2x^2-3)
= x^2 y^2 + 2x^2 y -3y + 4x^2y + 8x^2 - 12
= x^2 y^2 + 6x^2 y + 8x^2 - 3y- 12
got it
2006-06-12 08:36:56 · answer #2 · answered by keshu 2 · 0⤊ 0⤋
(y+4)(x^2y+2X^2-3)
=(x^2 y^2 + 2x^2 y - 3 y + 4x^2y + 8x^2 - 12 )
=x^2y^2 + 6x^2y + 8x^2 - 3y - 12
this is right
2006-06-12 08:45:14 · answer #3 · answered by Thava 1 · 0⤊ 0⤋
(y)(x^2 y+2x^2-3)+(4)(x^2 y+2x^2-3)
or (y+4)(x^2, y+2x^2-3) vector array?
( (y+4)(x^2), (y+4)(y+2x^2-3) )
2006-06-12 09:20:11 · answer #4 · answered by Spitrabergâ?¢ 4 · 0⤊ 0⤋
(x^2)(y^2) + (2x^2)(y) - 3y + (4x^2)(y) + 8x^2 -12
=(x^2)(y^2) +(6x^2)(y) - 3y - 12
2006-06-12 11:54:04 · answer #5 · answered by fatima 1 · 0⤊ 0⤋
(x^2)(y^2) + (2x^2)(y) - 3y + (4x^2)(y) + 8x^2 -12
=(x^2)(y^2) +(6x^2)(y) - 3y - 12
2006-06-12 08:58:10 · answer #6 · answered by Anonymous · 0⤊ 0⤋
x^2y^2+2x^2y-3y+4x^2y+8x^2-12
2006-06-12 08:32:20 · answer #7 · answered by Apoorva 3 · 0⤊ 0⤋
Now if that doesn't help then have a good day any way.
2006-06-12 09:08:15 · answer #8 · answered by Anonymous · 0⤊ 0⤋
x^2 y +2x^2 -3
* y +4
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x^2 y^2 +2x^2 y -3y
4x^2 y +8x^2 -12
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x^2 y^2 +6x^2 y -3y +8x^2 -12
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2006-06-12 08:47:33 · answer #9 · answered by K N Swamy 3 · 0⤊ 0⤋
gotcha!!!!
x^2y^2+6x^2y+8x^2-3y-12
2006-06-12 08:50:04 · answer #10 · answered by abhisek g 1 · 0⤊ 0⤋