2006-06-11 23:01:25 · 25 answers · asked by Lorraine * 1 in Science & Mathematics ➔ Mathematics
Depends on how many kisses were exchanged.
If each one kissed the other once:
11+10+9+8+7+6+5+4+3+2+1=66 unique kisses.
2006-06-11 23:05:45 · answer #1 · answered by wineasy03 6 · 0⤊ 0⤋
Assuming each person kisses every other person once:
11+10+9+8+7+6+5+4+3+2+1 = 66 kisses
2006-06-12 03:53:54 · answer #2 · answered by jimbob 6 · 0⤊ 0⤋
First of all, it's not 144. That says that all 12 people kiss 12 people which would include kissing themselves. Second if you count 12 people kissing 11 other people, you count each kiss twice.
The number of kisses is the number of pairs of people in a group of 12 that is the number of ways you can select a subset of 2 from a set of 12 which is 12!/2!10! = 66.
2006-06-11 23:17:24 · answer #3 · answered by rt11guru 6 · 0⤊ 0⤋
If kissing twice is allowed:
12 --- people
for every person, he/she can kiss one of the other 11 people (he/she can't kiss himself/herself):
(12)(11) = 132 kisses
If you want the kissing to be only once, divide it by two:
132/2 = 66 kisses
2006-06-11 23:16:10 · answer #4 · answered by PorkyBishop 2 · 0⤊ 0⤋
132
2006-06-12 15:15:37 · answer #5 · answered by Anonymous · 0⤊ 0⤋
132
2006-06-11 23:30:12 · answer #6 · answered by The_Champ_is_Here! 2 · 0⤊ 0⤋
132
2006-06-11 23:15:56 · answer #7 · answered by daydreamer 3 · 0⤊ 0⤋
132. I figured if they are 12 and each one get 11 kisses (12 besides the person self would be 11) then you multiply it, then you would get 132 kisses.
2006-06-11 23:08:16 · answer #8 · answered by *♥£öVe§♥* 3 · 0⤊ 0⤋
66
2006-06-12 02:40:02 · answer #9 · answered by MakingYouHappy 3 · 0⤊ 0⤋
66
2006-06-12 01:11:40 · answer #10 · answered by Just a Guy 4 · 0⤊ 0⤋