29 minutes (if they double every minute and it's full in 30 minutes, it has to be only half full after 29 minutes)
2006-06-11 17:36:29
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answer #1
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answered by jimbob 6
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29
2006-06-25 23:45:26
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answer #2
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answered by lkamh 2
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29 min... or in general, let y be the fraction of how full the jar is; and t the time in the jar
y = (1/2)^(30-t) or t = 30 - [ln(y)/ln(1/2)]
since y = 1/2
t = 30 - [ln(1/2)/ln(1/2)] = 30 -1 = 29
To find the time to fill a fraction f of a jar with x amount of bugs, that increase by a multiple of a, that fills in b minutes.
t = b - [ln(f)/ln(1/a)]
which is independent of the number of initial bugs
2006-06-12 03:49:48
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answer #3
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answered by Babatunde K 2
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29 mins, that last minute doubles the count to 30
2006-06-22 16:54:32
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answer #4
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answered by tubafizzle89 2
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29 minuts
2006-06-25 16:17:48
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answer #5
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answered by knepmom 1
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29 minutes.
2006-06-25 10:18:45
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answer #6
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answered by Anirudh 2
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hmmm... at 30 minutes it is full.. so the minute previous it was half full.. or at 29 minutes it was half full.. unless.. hmmm.. where do they get food and water and air? the jar can never be full of bugs if they are to have food and water and air!!
2006-06-23 23:41:50
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answer #7
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answered by ♥Tom♥ 6
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y = 2 * 2^(n - 1)
y = 2^1 * 2^(n - 1)
y = 2^(1 + (n - 1))
y = 2^(1 + n - 1)
y = 2^n
y = 2^30
y = 1073741824
1073741824/2 = 536870912
536870912 = 2^n
nln2 = ln(536870912)
n = (ln(536870912)))/ln2
n = 29
ANS : 29 minutes
2006-06-12 14:48:24
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answer #8
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answered by Sherman81 6
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Trick ?; Answer = 29 min
2006-06-12 00:36:42
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answer #9
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answered by Steve 7
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Not hard at all. 29 minutes.
2006-06-12 00:37:56
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answer #10
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answered by quietwalker 5
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