A bag contains 3 yellow marbles 5 blue & 4 red. If 2 are chosen at random 1 after the other without?

Question

replacement, what is the probability that both are yellow?
a. (1/4) * (1/5)
b. (1/4) * (2/11)
c. 1/4
d. 2/55
e. none

Answer 1

B...on ur first choice, u have a 3/12 chance (1/4)...assuming you draw a yellow marble on the first draw, there are only 2 yellow marbles left and there are only 11 total marbles (2/11)...so the answer is 1/4*2/11...

Answer 2

theres a total of 12 marbles, of which 3 of them are yellow, so the odds of picking a yellow is (3/12) or (1/4). If you take that out, you know have 11 marbles, of which 2 of them are yellow, so the odds of picking a yellow marble is (2/11)

The odds of picking a yellow marble twice in a row, is found like this

(1/4)(2/11) = (2/44) = (1/22)

ANS : B

Answer 3

3/12*2/11= (1/4)*(2/11) B

Answer 4

Answer is b.

Probability of 1st being yellow = 3/12 = 1/4
AND
Probability of 2nd being yellow = 2/11 (Number of yellow balls has reduced, as has the number in the set)

So combining the two events we get (1/4)*(2/11)

Answer 5

e. none

adding the numbers together you get 12. you are asking the probability that you take out two without repeating colors right? then 3/12 odds ratio that you get a yellow marble. but there is a 5/12 ratio that the marble will be blue. divide both fractions together then you shall get the answer

Answer 6

e. none beacuse if you were to choose 2 yellow it would be 2/14 which is 1/7. simple math

Answer 7

either B. or f. none of the above

Answer 8

The answer isn't listed, so e. (none).

Answer 9

E.none) is my answer.

Answer 10

huh?