2^(x+1) = 5^(1-2x)
please help!
2006-06-11 10:08:30 · 5 answers · asked by melanie 1 in Science & Mathematics ➔ Mathematics
2^(x+1) = 5^(1-2x)
log 2^(x+1) = log 5^(1-2x)
(x+1) log 2 = (1-2x) log 5
(log 2 + 2 log 5)x = log 5 - log 2
x = (log 5 - log 2)/(log 2 + 2 log 5)
2006-06-11 10:26:17 · answer #1 · answered by rt11guru 6 · 1⤊ 0⤋
Sorry. Don't know how to solve it, but the previous answer is incorrect. You mean [2 to the power of (x+1) = 5 to the power of (1-2x)], not [2 times (x+1) = 5 times (1-2x)], right?
2006-06-11 17:25:18 · answer #2 · answered by Teacher 2 · 0⤊ 0⤋
2x +2=5-10x
2x+10x=5-2
12x=3
x=3/12
x=1/4
2006-06-11 17:18:59 · answer #3 · answered by gabypalma 3 · 0⤊ 0⤋
2^(x + 1) = 5^(1 - 2x)
(x + 1)ln2 = (1 - 2x)ln5
xln2 + ln2 = ln5 - (2x)ln5
xln2 + (2x)ln5 = ln5 - ln2
x(ln2 + 2ln5) = ln5 - ln2
x = (ln5 - ln2)/(ln2 + 2ln5)
or
x = (ln5 - ln2)/(ln2 + ln25)
x = (ln5 - ln2)/(2ln5 + ln2) or (ln5 - ln2)/(ln25 + ln2)
I prefer (ln5 - ln2)/(2ln5 + ln2)
but they both mean the same thing.
2006-06-11 18:01:45 · answer #4 · answered by Sherman81 6 · 0⤊ 0⤋
is that even possible?
2006-06-11 17:11:15 · answer #5 · answered by Br 3 · 0⤊ 0⤋