Solve for n: s = c(1-d)^n?

Question

I forgot how to do lograthims. Heh.

Answer 1

s = c(1 - d)^n
(1 - d)^n = (s/c)
log(1 - d)(s/c) = n

ANS : n = log(1 - d)(s/c) or n = log(1 - d)s - log(1 - d)c

Whereas (1 - d) is the base

or you can type it like this

n = (log(s/c))/(log(1 - d))
or
n = (log(s) - log(c))/(log(1 - d))

Answer 2

I forgot too. Oops. That, or I havent even learn it yet. Take your pick...

Answer 3

log(s) = log[c(1-d)^n]
log(s) = log(c) + n*log(1-d)
n= [log(s)-log(c)]/log(1-d)