moidelamoi, How do you solve 4/(x+3) = 6/(4-x) ?

Question

***** I've got an exam tomorrow not homework!!!

Answer 1

4/(x+3)=6/(4-x)
=>4(4-x)=6(x+3)
=>16-4x=6x + 18
=>16 - 18 = 6x + 4x
=> -2 = 10x
=>-2/10 = x
=> -1/5 = x
=>x = -1/5
I did it by transposing terms and cross multiplying the first step. Since i've solved ur problem please please please please contact me. Remember I study in ninth standard and am a maths and science genius.............
By the way beeeeeeeest of luck for ur test

Answer 2

Cross multply first step:
4(4-x) = 6(x+3)
16-4x=6x+18
16=10x+18
-2=10x
-2/10=x
-1/5=x

Answer 3

you need to multiple by the denominator on both sides to bring each one to the opposite side, so you end up with:

4(4-x) = 6(x+3)
16 - 4x = 6x + 18
16 = 10x + 18
-2 = 10x
-2/10 = x
-1/5 = x

good luck!

Answer 4

4/(x+3) = 6/(4-x)

cross multiplying you get:

4( 4-x ) = 6 ( x + 3 )
16 - 4x = 6x + 18

16 - 18 = 6X + 4x
-2 = 10x
-2/10 = x
-1/5 = x

Answer 5

4/(x+3) = 6/(4-x)
4(4-x) = 6(x+3)
16 - 4x = 6x + 18
16 - 18 = 6x + 4x
-2 = 10x
x = -2 / 10
x = -1/5 or -0/2

Answer 6

(4/(x + 3)) = (6/(4 - x))
cross multiply
4(4 - x) = 6(x + 3)
16 - 4x = 6x + 18
-10x = 2
x = (-1/5)

Answer 7

u want all ur ques to be solved by us??
anyways here is the solution :
4(4-x)=6(x+3)
16-4x=6x+18
6x+4x=16-18
10x=-2
x= -1/5 or -.2

Answer 8

4/(x+3)=6/(4-x)
=> (4-x)/(x+3)=3/2
=>7/(x+3)=5/2
=>14=5x+15
=>x= -1/5

Answer 9

x=-1/5

Answer 10

4/(x+3)=6/(4-x)
4(4-x)=6(x+3)
16-4x=6x+18
-4x-6x=18-16
-10x=2
x= -0.2