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2C8H18 + 25O2 ---> 16CO2 + 18H2O

2 molecules of octane (which is not the only component of gasoline, and octane rating has nothing to do with how much octane is actually present) react with 25 molecules of oxygen to produce 16 molecules of carbon dioxide and 18 molecules of water.

2006-06-11 06:16:12 · answer #1 · answered by TheOnlyBeldin 7 · 2 0

properly shall we see C3H8 + ?O2 ---> ?H2O + ?CO2 C3H8 + (X)O2 ---> (Y)H2O + (Z)CO2 To stability a combustion reaction you could desire to: first count variety the type of carbon interior the final compound (propane) that's 3 assign it for CO2 instead of (Z) then count variety the type of hydrogen that's 8 then assign it for H2O instead of (Y) finally count variety the type of oxygen O interior the products which would be (4*2 + 4 = 10) then divide it by 2 = 5 because of the fact of O"2" finally you will discover that the equation C3H8 + 5O2 ---> 4H2O + 3CO2 is balanced

2016-12-08 08:20:31 · answer #2 · answered by ? 4 · 0 0

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