YOU MUST SOLVE BY FACTORING!!!
2006-06-11 06:05:40 · 8 answers · asked by swtmoney116 3 in Science & Mathematics ➔ Mathematics
x ~2 + 3x = 54
=> x~2 + 3x -54 = 0
=> x~2 + 9x - 6x -54 = 0
=> x(x+9) - 6(x + 9)=0
=> (x-6)(x+9) = 0
=> x=6
=> x = -9
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2006-06-11 06:31:27 · answer #1 · answered by Anonymous · 7⤊ 3⤋
First the equation must look like:
x-squared + 3x - 54 = 0
Then Factor so:
(x-6) (x+9)
This means that x = 6, -9
2006-06-11 13:10:17 · answer #2 · answered by Stacey 2 · 0⤊ 0⤋
6
2006-06-11 13:08:02 · answer #3 · answered by frenchy62 7 · 0⤊ 0⤋
x^2 + 3x = 54
x^2 + 3x - 54 = 0
(x + 9)*(x - 6) = 0
x = {-9, 6}
As far as factoring in my head goes, I just think of what factors of -54 add up to 3.
2006-06-11 13:43:05 · answer #4 · answered by Baseball Fanatic 5 · 0⤊ 0⤋
x^2 + 3x = 54
can rewrite as
x^2 + 3x - 54 = 0
factors for -54 are 9 and -6
so write as
x^2 + 9x - 6x - 54 = 0
x ( x + 9 ) - 6( x + 9 ) = 0
( x - 6 ) ( x + 9 ) = 0
x = 6
x = - 9
2006-06-11 13:10:56 · answer #5 · answered by M 1 · 0⤊ 0⤋
x^2 + 3x - 54 =0
(x+9)(x-6)=0
x = 6 or -9
2006-06-11 13:12:18 · answer #6 · answered by Anonymous · 0⤊ 0⤋
x*2+3x=54
x*2+3x-54=0
(x+9)(x-6)=0 * Your Answer*
Because the answer has +3x, x+9 must come first because when you add your answer (x+9)(x-6)=0, it must agree to the solution you worked out with.
2006-06-11 13:11:24 · answer #7 · answered by Anonymous · 0⤊ 0⤋
if you dont know just use the quadratic equation
x^2 + 9x - 6x - 54 = 0
x(x+9) - 6(x+9) = 0
(x-6)(x+9) = 0
2006-06-11 13:08:48 · answer #8 · answered by dtstuff9 6 · 0⤊ 0⤋