Math question!!!!?

Question

There are 200 l water in the 2 barrels.If transfer 1/4 l from the first barrel to second,then it will be 20 l water more in the second barrel than in the first one.How many l water in the first barrel and in the second?
Thx a lot for full solution..

Answer 1

if you have x l in the first, so (200-x) l will be in the second barrel
x/4 l - goes from first to second
so you have 3*x/4 in the first barrel and (200-3*x/4) l in the second,
and 3*x/4+20 = 200-3*x/4
(you must add 20 l to the first because the water there is less and you need an equality)
3*x/4+20*4/4 = 200*4/4 - 3*x/4
3*x+80 = 800 - 3*x
6*x = 720
so x = 120
you have 120 l in the first and 80 l in the second barrel

Answer 2

After the transfer of a quarter of a litre of water, barrel 2 has 110 litres and Barrel 1 has 90 litres.

So before the transfer, barrel 1 had 90.25 litres and Barrel 2 had 109.75 litres,

I suspect however that you may mean a quarter of the contents of barrel 1 are transferred. In which case barrel 1 started with 120 litres and ended with 90 litres and barrel 2 started with 80 litres and ended up with 110 litres.

Or you may mean that what is transferred is one quarter of the total amount of water ie 50 litres. If so then Barrel 1 started with 140 litres and ended with 90 litres and Barrel 2 started with 60 litres and ended with 110 litres.

The next answer must be wrong because there is not a difference in the contents of the two barrels of 20 litres, at the end of the process. The algebra got tangled, I fear.

Answer 3

120

Answer 4

Lets assume barrel1=x,barrel2=y
x+y=200
x-1/4x=y+20,
3/4x=y+20
3x/4=y+20
3x=4(y+20)
3x=4y+80
3x-4y=80
3(200-y)-4y=80
600-3y-4y=80
600-7y=80
-7y=80-600
-7y= -520
7y=520
y=520/7
y=74.29(app)
then x=200-74.29=125.71


So, first barrel contains 125.71 litres
and the second one contains 74.29litres

Answer 5

its confusing

Answer 6

i need a calcalator....

Answer 7

why?