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2006-06-10 01:46:45 · 4 answers · asked by sweetgurl 1 in Science & Mathematics Chemistry

2H2 +O2 >2H2O

2006-06-10 01:49:04 · update #1

PLEASE SEE THE BALANCED EQUATION

2006-06-10 01:58:09 · update #2

4 answers

To find amount of water produced, first , we need to write a balanced equation for the reaction:

2H2 + O2 = 2H2O

To do any Stoechiometry calculations we need to change the grams to moles.

1 g H2 * 1 mol/2.016 g = .496 moles of H2
10 g O2 * 1 mol /32 g =.3125 moles

The ratio between H2 and H2O in the balance equation is 1:1
On the other hand, the ratio between O2 and H2O in the balanced equation is 1:2.
That means we can make .496 moles of H2O from the given H2 and 03125*2 = .625 moles of H2O from the given O2. In this case H2 is the limiting reactant since H2 will run out first. That means we can only make .496 moles of H2O from the given H2 and O2.
Now we need to change the moles of H2O to grams.
.496 moles * 18.016 g/1 mol H2O = 8.936 grams.

2006-06-10 01:47:48 · answer #1 · answered by organicchem 5 · 1 1

2g of H with 16 g of O forms 18 g of H20

1g of H with 8 g of O forms 9 g of H20


Thus 9 g of water will form

2006-06-10 08:50:33 · answer #2 · answered by ag_iitkgp 7 · 0 0

1.25 grams of water or about 1.25 ml
or about .00125L

2006-06-10 08:55:21 · answer #3 · answered by loligo1 6 · 0 0

none

2006-06-10 08:49:14 · answer #4 · answered by Steve 7 · 0 0

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