2006-06-10 00:29:52 · 6 answers · asked by monti 1 in Science & Mathematics ➔ Mathematics
80=16*5
log(2^4*5)/log2
=(log2^4+log5)/log2
=(4 log2+log(10/2))/log2
=(4log2+log10-log2)/log2
=(3log2+1)/log2=3+(1/log2)
2006-06-10 01:15:41 · answer #1 · answered by iyiogrenci 6 · 0⤊ 1⤋
Since .8 = 4/5, log(.8) = log 4 - log 5. Dividing by log 2 and applying change of base rule, you get 2 - log5 / log2. This is actually irrational, so this is your answer.
2006-06-22 12:48:42 · answer #2 · answered by vishalarul 2 · 0⤊ 0⤋
Log .8 / log 2 = log (8/10) / log 2 = log (8/10) * log (1/2)=log 8/10 + log 1/2
2006-06-10 12:04:50 · answer #3 · answered by Kenneth Koh 5 · 0⤊ 0⤋
Try it yourself. Try changing log .80 to something which will cancel log 2 & you have your answer.
2006-06-23 03:42:39 · answer #4 · answered by nayanmange 4 · 0⤊ 0⤋
log(.80)=log 80/100=
2006-06-10 11:59:10 · answer #5 · answered by gari 3 · 0⤊ 0⤋
80=16*5
log(2^4*5)/log2
=(log2^4+log5)/log2
=(4 log2+log(10/2))/log2
=(4log2+log10-log2)/log2
=(3log2+1)/log2=3+(1/log2)
oops!! I cheated
2006-06-10 09:16:47 · answer #6 · answered by sarathraj 2 · 0⤊ 0⤋