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2006-06-08 18:27:59 · 15 answers · asked by hector c 1 in Science & Mathematics Physics

15 answers

Gravity exerts a slightly less force at higher altitudes, even though it is almost non-existent. If you were to weigh yourself at sea level and then again on top of Mt. Everest, you would weigh less on top of the mountain. (Again, very, very, very little change).

2006-06-08 18:31:40 · answer #1 · answered by benbobbins 3 · 0 0

No. It's less, but the difference on Earth is so small you can ignore it (because for most purposes you won't be using anything that can measure that small of a difference anyway)

In most science courses this is what they mean when they say the difference is negligable.

Why is there a difference and why is it so small? Well if you look at the equation for the force of gravity between two objects you can see how the force of gravity depends on the masses of the objects and the distance between them.

the Force of Gravity Fg= G ( m1 x m2 )/ r2 .

G is a constant that makes the units come out to be Newtons (measurement of force) m1 is the mass of one object l(ike you) and m2 is the mass of the second object (like Earth) and r is the distance between them.

Let's say G x m1 x m2 are going to be the same. After all G is a constant, and your mass and the earth's mass are going to be the same.

So lets just call that (G x m1 x m2) = 1 and see what happens when you change the distance between the centers of the objects (you and earth) and move you apart one foot at a time.

1/ 1^2 = .5
1/2^2 = .25
1/3^2 = .111

You can see moving the objects away makes the force get small realy quickly.

Infact the rate at which gravity decreases as objects move away is really fast. This is becase the distance is on the bottom of the fraction and squared. This is called an inverse square law.

But I said the difference in 25 feet and 300 feet was so small you couldn't tell, right?

That's because of two things, the really big mass of the earth and the fact that the distance in the equation is the distance between the centers of the objects.

The change in distance is really small with the numbers we're using because the distance between the centers includes the radius of the Earth. 6378135 m + 25 feet (about 8 meeters) squared and in the second case it's 6378135 m + 300 feet (about 100 meters) squared. So in one case you have Fg = (Gm1m2)/(6378143)^2 and in the second case you have Fg + Gm1m2)/(6378335)^2. So at 25 feet it's
Gm1m2) x .0000000000000245816

and at 300 feet you get Gm1m2 x .0000000000000245802

There's no change in the values until the 19th decimal place. The difference in the force is about 1 quintillionth of a Newton.

2006-06-14 10:08:45 · answer #2 · answered by bulldog5667 3 · 0 0

Understanding Gravity is to dismiss Newton. He was OK for a time, but we have learned a lot more in the past 100 years. The world is not flat, but of coarse you already knew that. During the moon landings one experiment was conducted to prove one of Newtons Laws and it was when a feather was dropped at the same time as a brick they would fall at the same velocity and strike the surface of the moon at the same time. This was proved to be so. You know this would not happen here on Earth due to the Atmosphere. On Earth we have a term called Terminal velocity and this is in relation to the mass, again a Earth thing. To answer the question is to focus on the Gravity. The force is Equal regardless. Why?
Gravity is a phenomena of Electricity and electricity is a phenomena of magnetism. They are both the same, yet we do not think so because of the definitions we use to describe either one. To make a long story short...it takes three things to cause gravity to be. (1.) a transmitter, ie. SUN. (2.) Receiver, ie. Earth & (3.) an item acted upon, ie. You on Earth. Remove anyone of the three and there is no Gravity. Understanding the Universe is simple. Gravity is the ORDER of the Universe. Replace the SUN with the Galixy, the Earth with the solar system and You with the Planets. Get the picture?

2006-06-09 02:02:47 · answer #3 · answered by blueridgemotors 6 · 0 0

Technically, the farther away from the Earth you are, the lower the force exerted on you. The formula for the force between two objects is:

[G (Gravitational constant for Earth)x mass1xmass2]/r^2

Where mass 1 and mass 2 are the two masses (Earth and object) and r is the distance between the two objects.Now, you may be thinking, "Well if the distance is increased by 12 (300/25), surely the Force goes down by a multiple of 12^2=144.

But when we measure "r" we imagine that we take a line from the center of the object to the center of the Earth. Given that an extra 275 feet doesn't make a heck of a lot of difference when the thousands of miles to the center of the Earth are added, you can imagine that the change in gravitational force is miniscule.

But there is a difference, ever so slight, and when you are at a height of 300 feet the Earth exerts a force maybe in the order or .99999999% of that at 25 feet, so pretty much the same for practical purposes.

But when you go really far out- to space even- then it does make a noticeable difference.

2006-06-09 01:42:59 · answer #4 · answered by bloggerdude2005 5 · 0 0

There will be a very small difference. Gravity will exert a lesser force at 300 ft than at 25 ft but it is barely noticable.

2006-06-09 01:34:13 · answer #5 · answered by avik_d2000 4 · 0 0

well, techinally no...the formula for gravitational force between two objects is F=GMm/r^2, where G is the gravitational constant=6.67 x 10^ -11. M is the mass of the bigger object (in this case Earth (5.97 x 10^24) and m is the smaller mass (your mass) and r is the distance from the center of the earth (6403.1 km and 6678.1 km), meaning your difference is extremely fractional.

2006-06-09 01:40:01 · answer #6 · answered by Anonymous · 0 0

yes there is a weaker pull the farther away from the planet you get. Which means if you want to lose wheit climb a mountain. But the amount of pull lost is miniscule you would need to get extreamly far away from the earth to notice a difference

2006-06-09 01:34:47 · answer #7 · answered by treisigbob 3 · 0 0

the value of gravity depend on the distance from an imaginary line drawn that divide the earth in two parts.The value of gravity is maximum at the poles and is minimum at the equator where distance from the line is maximum

2006-06-09 01:32:52 · answer #8 · answered by Rachit Sood 2 · 0 0

no, there is a very slight difference, but not enough to measure. the farther away from the center of the earth you are, the less gravity there is. that's why you are weightless in outer space

2006-06-09 01:31:56 · answer #9 · answered by ErasmusBDragen 4 · 0 0

Yes, I think that the answers given will help you make a good choice in picking the right answer.

2006-06-09 05:22:03 · answer #10 · answered by einstein 4 · 0 0

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