2006-06-08 15:03:14 · 6 answers · asked by nick 2 in Science & Mathematics ➔ Chemistry
The listed percentage of vinegar is almost always "by weight" and not volume.
10% vinegar means that 10% of the weight of the vinegar is acetic acid, the other 90% is water.
To calculate the molality, we need to figure out how many moles of a solute (acetic acid) is dissolved in the solvent (water).
We need also calculate the volume of the solution (in liters).
To solve this, take (for example) a 100 gram sample of 10% acetic acid, this would mean that 10 grams out of 100 are acetic acid. Knowing the molar mass of acetic acid (60.05 g/mol) we can calculate the number of moles of acetic acid present.
10 g / 60.05 g/mol = .1665 moles
A 10% acetic acid solution has a density very close to that of water, so it is not unreasonable to just assume a density of 1 g/cm^3 (if you want a more accurate answer, look up the density your self). If we assume the density is 1 g/cc, then 100 grams of 10% vinegar would have a volume of 100 mL, or .1 Liters.
We now know the number of moles of solute and number of Liters of solution, we can calculate molarity.
M = moles / Liter
M = .1665 moles / .1 Liter
M = 1.665 Molar
2006-06-08 15:20:46 · answer #1 · answered by mrjeffy321 7 · 0⤊ 0⤋
10 Percent Vinegar
2016-12-29 15:02:20 · answer #2 · answered by Erika 3 · 0⤊ 0⤋
10 Vinegar
2016-09-29 10:19:59 · answer #3 · answered by kaad 3 · 0⤊ 0⤋
Apple Cider Vinegar eBook : http://AppleCiderVinegar.siopu.com/?Svw
2016-06-23 00:25:44 · answer #4 · answered by ? 3 · 0⤊ 0⤋
10g of vinegar dissolved in 100 ml of solutions
2006-06-10 06:09:06 · answer #5 · answered by fazi 3 · 0⤊ 0⤋
Assuming you mean 10% weight/volume acetic acid,
which is in say g/L, to convert to mol/L simply divide this percentage by the molar mass of acetic acid:
(10g/L)/(60g/mol) = 0.167 mol/L
2006-06-08 15:11:28 · answer #6 · answered by Robert L. D 2 · 0⤊ 0⤋