f(x) = x3 e(8x2), then what is f ' (1)? (express your answer as a number rounded to three decimal places)?

Question

First person to answer correctly will get the best answer points.

Answer 1

f'(x) = (x^3)'e^(8x^2) + (x^3)(e^(8x^2))'
f'(x) = (3x^2)e^(8x^2) + (x^3)(16xe^(8x^2))
f'(x) = (3x^2)e^(8x^2) + (16x^4)e^(8x^2)
f'(1) = 3e^8 + 16e^8
f'(1) = 19e^8
f'(1) = 56638.202

Answer 2

f(x) = x³ e^(8x2)

= x³e^(16)

f'(x) = (e^16)*3x² , as e^(16) is a number

f'(1) = (e^16)*3(1)² , substituting x=1
= (e^16)*3
= 8 886 110.496*3
= 26 658 331.489


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or if u meant f(x)= x³ e(8*2)

then,
f(x) = x³ * 16e
= 16ex³
f'(x) = 16e * (3x² )
= 48ex²

f'(1) = 48e(1)²
= 48e
= 104.558

Answer 3

f(1)=1X3? e(8X2)< huh?

is it x^3 (third power)?

I understood it as 1X3X16e which would be 48e.