Prove that there are no nonzero integers x, y, & z such that x^n+y^n=z^n where n is an integer greater than two.
2006-06-08 14:05:00 · 4 answers · asked by Grant H 2 in Science & Mathematics ➔ Mathematics
haha, thats crazy to ask.
basically, this was proven by andrew wiles in 1994, and resubmitted after an error was found
he developed new mathematics that will basically be the foundation of study in the coming century.
the level of mathematics that would be required to understand the proof most PhD mathematicians dont have.
sorry
wish i could be more help
matttlocke
2006-06-08 15:18:52 · answer #1 · answered by matttlocke 4 · 0⤊ 0⤋
A guy proved that in the 90's and in a site I found "The proof was published in May of 1995 in
the Annals Of Mathematics (filling up more than 140 pages!). The
proof is based on the theory of elliptic curves and involves a lot of
high-powered mathematics. "
However to me is more or less evident, remember that the equation above is a coincidence, nothing else:
consider n=3, consider that powers are getting away from each other more and more has from the x or y increases. so if there is any number for each it should work is not in huge number but in rouder small ones now do a table of x and y ( varing from 0 to 20) cube it and compare it with the nearest z that could obey to the equation above.compare both after a wile they get to distant from each other. To me its proved to n=3 to the math comunity it's not.
for n>3 the reasoning it's the same, and it is even more obvius.
2006-06-08 14:31:31 · answer #2 · answered by Anonymous · 0⤊ 0⤋
The proof for that theorem required pages and pages of math. Much more than Yahoo! probably provides in a single answer on Yahoo! answers.
2006-06-08 14:30:14 · answer #3 · answered by KJCC 2 · 0⤊ 0⤋
Anyone that can include a proof on answers.yahoo.com deserves the 10 points. Hell, I'll create 10 questions and give you ten points for each.
2006-06-08 14:20:07 · answer #4 · answered by Eulercrosser 4 · 0⤊ 0⤋