No. The closest thing that you can do is find an inverse, if the matrix is non-singular.
Addenda: You can't "Just take the inverse of the second matrix and multiply." Not all matrices have inverses.
For example:
|1 0|
|0 0|
doesn't have an inverse.
2006-06-08 08:41:44
·
answer #1
·
answered by rt11guru 6
·
0⤊
0⤋
Yes. Just take the inverse of the second matrix and multiply. For numbers, a / b is defined as a * 1/b. So for matrices, A / B = A * inverse(B). (That's why inverse is generally written as B to -1 power.)
Just remember that matrix multiplication is not commutative, so A / B is not equal to B^-1 * A, only to A * B^-1.
This isn't really called "dividing", actually. It is just multiplying by the inverse. But it is dividing in the sense that if:
A * B = C
A * B * B^-1 = C * B^-1
A = C * B^-1
where you're "dividing" both sides by B.
2006-06-08 08:43:27
·
answer #2
·
answered by geofft 3
·
0⤊
0⤋
12/3=4 because 4 x 3 = 12
Do the same with matrices! Then u can use matrix multiplication.
If the matrices are n x n, u find n equations.
2006-06-08 10:36:47
·
answer #3
·
answered by Thermo 6
·
0⤊
0⤋
Division of matrices is unknown in the field of mathematics.
The lateral division is however carried out by mutiplying the inverse of the divisor matrix to be divided matrix.
[A] divided [B] = [A] X [B]-1
This is however not formally recognised as the division of matrices.
2006-06-08 08:46:05
·
answer #4
·
answered by soloman_arcade 1
·
0⤊
0⤋
Yes
there is both left and right division
2006-06-08 08:45:47
·
answer #5
·
answered by Anonymous
·
0⤊
0⤋
NERD
2006-06-08 14:54:30
·
answer #6
·
answered by <H3R0!n3> 2
·
0⤊
0⤋