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2006-06-08 08:38:13 · 6 answers · asked by Anonymous in Science & Mathematics Mathematics

6 answers

No. The closest thing that you can do is find an inverse, if the matrix is non-singular.

Addenda: You can't "Just take the inverse of the second matrix and multiply." Not all matrices have inverses.

For example:
|1 0|
|0 0|
doesn't have an inverse.

2006-06-08 08:41:44 · answer #1 · answered by rt11guru 6 · 0 0

Yes. Just take the inverse of the second matrix and multiply. For numbers, a / b is defined as a * 1/b. So for matrices, A / B = A * inverse(B). (That's why inverse is generally written as B to -1 power.)

Just remember that matrix multiplication is not commutative, so A / B is not equal to B^-1 * A, only to A * B^-1.

This isn't really called "dividing", actually. It is just multiplying by the inverse. But it is dividing in the sense that if:
A * B = C
A * B * B^-1 = C * B^-1
A = C * B^-1
where you're "dividing" both sides by B.

2006-06-08 08:43:27 · answer #2 · answered by geofft 3 · 0 0

12/3=4 because 4 x 3 = 12
Do the same with matrices! Then u can use matrix multiplication.
If the matrices are n x n, u find n equations.

2006-06-08 10:36:47 · answer #3 · answered by Thermo 6 · 0 0

Division of matrices is unknown in the field of mathematics.
The lateral division is however carried out by mutiplying the inverse of the divisor matrix to be divided matrix.
[A] divided [B] = [A] X [B]-1
This is however not formally recognised as the division of matrices.

2006-06-08 08:46:05 · answer #4 · answered by soloman_arcade 1 · 0 0

Yes

there is both left and right division

2006-06-08 08:45:47 · answer #5 · answered by Anonymous · 0 0

NERD

2006-06-08 14:54:30 · answer #6 · answered by <H3R0!n3> 2 · 0 0

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