2006-06-08 08:06:31 · 14 answers · asked by jaya b 1 in Education & Reference ➔ Teaching
10%
2006-06-08 08:11:07 · answer #1 · answered by Anonymous · 0⤊ 0⤋
Around 9 percent. If A earns 110 and B earns 100, add 10% of A's earnings is 11, so B earns roughly 9% less. (110-11=99)
If A earns 66, then B would earn 60, and again the proportion is about 9.1%
So yeah, roughly 9%
2006-06-08 08:14:59 · answer #2 · answered by turtlemascot103 2 · 0⤊ 0⤋
About 9%
2006-06-15 07:38:46 · answer #3 · answered by Osker 1 · 0⤊ 0⤋
A=110. B=100. (110-100)/110=0.090909 or 9.0909%.
2006-06-08 08:14:02 · answer #4 · answered by robertspraguejr 4 · 0⤊ 0⤋
1/11 * 100 = answer.
roughly 9.090909%
2006-06-08 08:11:00 · answer #5 · answered by Anonymous · 0⤊ 0⤋
5%
2006-06-08 08:09:32 · answer #6 · answered by Anonymous · 0⤊ 0⤋
9%
2006-06-08 08:12:25 · answer #7 · answered by Anonymous · 0⤊ 0⤋
good one
The 9.09 people are of course right
2006-06-08 08:46:10 · answer #8 · answered by hunter 4 · 0⤊ 0⤋
Just a guess 10%...
2006-06-08 08:09:44 · answer #9 · answered by sweet 4 · 0⤊ 0⤋
10% less!
2006-06-08 12:45:19 · answer #10 · answered by just julie 6 · 0⤊ 0⤋