Chem Question 2?

Question

A compound has the empirical formula CHCl. A 256 mL flask, at 373 K and 750. torr, contains 0.800 g of the gaseous compound. Give the molecular formula. (Type your answer using the format CH4 for CH4.)

Answer 1

PV=m/MM * RT
PV/RT = m/MM
MM = mRT/PV = 0.800g * 0.08206 * 373/ ((750/760) * 0.256) = 96.9 g/mol

CHCl is 47.5 g/mol, so molecular formula is C2H2CL2.