Can someone please tell me how to sovle this?

Question

This is the problem: The cashier's drawer has four more nickles than dimes in it.The value of the nickles and dimes together is $2.45.How many dimes are there?- Someone help!

Thanks to all the people who sent me answers .It really helped me understand the problem better. To the people who chose not to answer and be rude and snippy, I did try to sovle it .About 20 times actually .I was just asking for help which is why this website exists in the first place .

Answer 1

This is my solution.

Let x be the number of nickels and y be the number of dimes.

We already know one equation, which is x = y +4, which means that The cashier's drawer has four more nickles than dimes in it.

Then 5x +10y = 245, which means that x(the number of nickels) times 5cents each plus y(the number of dimes)times 10 cents each is 245 cents. Therefore, substituting the first equation to the second:

5(y+4) + 10y = 245.
5y +20 + 10y = 245.
15y = 225.
y = 15.

Therefore there are 15 dimes. And if you need to find the number of nickels, simply:

y + 4
15 +4
19 = x.

There are 19 nickels.

Answer 2

It's actually possible to solve this problem without using any algebraic formulae -- but please understand, your teacher might not give you credit for this approach, since it *is* an algebra class. Still, this is a practical way to check your answer.

The drawer has four more nickels than dimes -- you can think of this as a whole bunch of "nickel-dime pairs" and four stray nickels.

Four nickels makes 20 cents, and when we take that 20c from the $2.45, we have $2.25 left, which must be composed of our "nickel-dime pairs." Of course, the value of each n-d pair is 15 cents.

So, how many n-d pairs are in the remaining $2.25? We divide $2.25 by 15c (written as $0.15) and get 15. There are 15 nickel-dime pairs, which means there are 15 dimes. (And, although the problem didn't ask for it, there are 15 nickels from the n-d pairs plus the four "straggler" nickels, for 19 nickels total.)

That matches the algebraic solution given by others, which is a darn good sign. :)

Answer 3

n = number of nickels
d = number of dimes

n = d + 4 (four more nickels than dimes)
.05n + .10d = 2.45 (the value of the coins is $2.45

Substitute (d + 4) for n

.05(d + 4) + .10d = 2.45
.05d + .2 + .10d = 2.45
.15d = 2.25
d = 15 (there are 15 dimes in the drawer)

(by the way, there are 19 nickels)

Answer 4

15 dimes. 19 nickels.

X=number of dimes.

.1(x)+.05 (x+4)=2.45

Answer 5

10 dimes in all

Answer 6

n=nickles
d=dimes
n=4+d (1)
5n+10d=245, but from (1) above
5(4+d)+10d=245
20+5d=10d=245
15d=225
d=15, n=19

Answer 7

Im Not doing your home work 4 u

Answer 8

the above man is right ..its so easy but i beleive u should solve it on ur own ...at least give a solution and ask is that right..so that u should not only get ur homework done but also some skills