2006-06-08 01:36:16 · 8 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
i have to solve the equation.....
2006-06-08 01:47:43 · update #1
√x+4=3 when I look at this I say 5……I just don’t know how to put it down………
2006-06-08 01:50:28 · update #2
x√18-3√8x^2……..please help I have to simplify……
2006-06-08 02:05:00 · update #3
no. very far. if y=13
sqrt(2)y=13-7-4=2
sqrt(2)y=2...y=sqrt(2)<<<13 so u contradicted yourself here.
if u mean sqrt(2)sqrt(y)... it's far too
sqrt(2)sqrt(y)=2 sqrty=sqrt2, y=2<<<13
or do u mean
√(2y+7)+4=y
2y+7=(y-4)^2
2y+7=y^2 +16 -8y
y^2-10y+9=0
(y-9)(y-1)=0
y=1 and y=9.... still.. far from 13
2006-06-08 01:49:46 · answer #1 · answered by Anonymous · 0⤊ 0⤋
y= +3 to -3
2006-06-08 10:00:48 · answer #2 · answered by Toy 2 · 0⤊ 0⤋
if by this you mean
sqrt(2y + 7) + 4 = y
sqrt(2y + 7) = y - 4
square both sides
2y + 7 = (y - 4)^2
2y + 7 = (y - 4)(y - 4)
2y + 7 = y^2 - 4y - 4y + 16
2y + 7 = y^2 - 8y + 16
y^2 - 10y + 9 = 0
(y - 9)(y - 1) = 0
y = 1 or 9
if you are not sure of your answer, just plug it in.
2006-06-08 08:50:18 · answer #3 · answered by Sherman81 6 · 0⤊ 0⤋
The notation is a bit ambiguous. The last two answers reflect this. You may want to elaborate: is it sqrt(2y), or sqrt(2)*y?
2006-06-08 08:44:34 · answer #4 · answered by anonymous 7 · 0⤊ 0⤋
sqrt(2y)+11=y
sqrt(2y)=y-11
2y=y^2-22y+121
y^2-24y+121=0
find the roots...
2006-06-08 08:40:56 · answer #5 · answered by mikedotcom 5 · 0⤊ 0⤋
no. u need to rationalise i. when u rationalise it, u get -26.5 and i'm sure of the answer
2006-06-08 08:42:03 · answer #6 · answered by agent 007 2 · 0⤊ 0⤋
im just as confused as u r
2006-06-08 17:13:35 · answer #7 · answered by Anonymous · 0⤊ 0⤋
sqrt(2y)=
2006-06-08 12:12:29 · answer #8 · answered by gari 3 · 0⤊ 0⤋